The solution to the given expression is x = -20/11
<h3>
What are logarithmic functions?</h3>
Logarithmic function are inverse of exponential functions. Given the equation below;
log (6 x + 10) = log 1/2 x
In order to determine the solution to the given logarithmic equation, we will first have to cancel the logarithm on both sides to have
6x + 10 = 1/2x
Collect the like terms
6x - 1/2x = 0 - 10
Find the LCD
12x-x/2 = -10
11x/2 = -10
Cross multiply
11x = -2 * 10
11x = -20
Divide both sides by 11
11x/11 = -20/11
x = -20/11
Hence the solution to the given expression is x = -20/11
Learn more on log functions and graph here: brainly.com/question/2086094
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34° is possible for the other two angles.
180°-112°=68°
68°/2= 34°
Answer:
$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Normally distributed with mean $480 and standard deviation $20.
This means that 
How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?
This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.




$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
48 becuase six times 8 is 48 not sure but hope this helps you