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Brums [2.3K]
2 years ago
9

Round 9,675,599 to the nearest 1,000.

Mathematics
2 answers:
BARSIC [14]2 years ago
7 0

Answer: 9,676,000

Step-by-step explanation:

Increase the digit by 1 if the previous digit is 5 or above

lora16 [44]2 years ago
7 0

Answer: 9676000

Step-by-step explanation:  you have to go the thousands place and round up because anything 5 or below round up

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Natasha has four nickels to dimes and 6 quarters in her pocket what is a theological probability that she will randomly select a
My name is Ann [436]

Answer:

1/2

Step-by-step explanation:

There are 4 nickels, 2 dimes, and 6 quarters. That means a total of 12 coins, half of which are quarters.

(realistically, if she wanted to, she could probably get a quarter every time if she felt for the size)

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HELP PLEASE 15PTS + BRAINLIEST
irakobra [83]

Answer:


Number of points, x, Number of segments, y

x: 2, 3, 4, 5, ... N,. ...

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6 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
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3 years ago
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