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3 years ago

Describe the modem system of cassification,

1 answer:

5 0

Answer: The system classifies organisms into eight levels: domain, kingdom, phylum, class, order, family, genus, and species.

Explanation:

The scientific name given to an organism is based on binomial nomenclature.

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How many grams of nh3 can be produced from 3.72 mol of n2 and excess h2.

olganol [36]

N₂ + 3H₂ ⇒ 2NH₃
1mol : 2mol
3,72mol : 7,44mol

n = 7,44mol
M = 17g/mol

m = n * M = 7,44mol * 17g/mol = 126,48g

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3 years ago

Which of the following statements about the combustion of glucose with oxygen to form water and carbon dioxide (C6H12O6 + 6 O2 →

KATRIN_1 [288]

Answer:

what are your statements?

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3 years ago

How many grams of H2 will be produced, given 27.4 g of Al to start with?

pishuonlain [190]

3.07g H2

27.4/26.98/2x3x1.01x2=3.07

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3 years ago

Tails of phospholipids that don't like water

densk [106]

Those tails are called hydrophobic. You can note the etymology: hydro= water, phobi = fear, aversion, dislike.

Phospholipds' tail is a long non polar chain, made of Carbon and Hydorgens, that rejects water (a polar solvent) and is attracted to non-polar compounds (oil for example). That is why that tails can atract dirt.

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3 years ago

A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase

Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298} = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\$

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

$V_{2} = \frac{58752}{4023}\\\\$

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

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2 years ago