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igomit [66]
3 years ago
12

A student chromatographs a mixture and after developing the spots with a suitable reagent he observes the following

Chemistry
1 answer:
Anika [276]3 years ago
6 0

Rf value is the ratio of the distance traveled by the solute to that of the solvent front on the paper used in chromatographic separation.

From the image it is clear the distance traveled by solvent front = 7.3 cm

Distance traveled by the component -1 of the mixture = 1.4 cm

Distance traveled by the component -2 of the mixture = 3.0 cm

Distance traveled by the component -3 of the mixture = 4.5 cm

Distance traveled by the component -4 of the mixture = 6.5 cm

Rf value of component-1 = \frac{1.4 cm}{7.3 cm} =0.192

Rf value of component-2 = \frac{3.0 cm}{7.3 cm} =0.410

Rf value of component-3 = \frac{4.5 cm}{7.3 cm} =0.616

Rf value of component-4 = \frac{6.5 cm}{7.3 cm} =0.890

b) Samples can be separated from a mixture using chromatography as the relative affinities for the compounds towards the paper (stationary phase) and the solvent(mobile phase) are different. Each component spends different amounts of time on the stationary phase depending on it chemical nature. So, the components in a mixture can be separated based on their polarities and relative degrees of adsorption on the stationary phase.








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Answer:

P_{He}=9.06torr

Explanation:

Hello there!

In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:

P_{He}=x_{He}P_T

Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:

n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189

Then, we calculate the partial pressure as shown below:

P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr

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Alexandra [31]
Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

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