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SOVA2 [1]
3 years ago
5

Which statement illustrates the difference between a chemical reaction and a nuclear reaction?

Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0
The answer is A)

A nuclear reaction releases more energy per gram and appears to violate the law of conservation of mass.
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Which of the following is not a base
SVEN [57.7K]
The answer is H₃C₆H₅O₇ (OPTION D).

In essence, the question is asking which of the options is an acid or a neutral compound; thus not a base.  A base is a compound that accepts free hydrogen ions while in aqueous solution and as such they usually lack hydrogen ions that can be released in solution.  If you ionize all the compounds/molecules above, the only on that has free hydrogen ions is OPTION D (which is an organic acid and not a base).
3 0
3 years ago
How many moles of HCl are present in 1.30 L of a 0.50 M solution
Shtirlitz [24]

Answer:

0.65moles of HCl was produced

4 0
2 years ago
Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
Cr^2+ is  the  chromium  ion   with  oxidation  state  of  two  which  is  one  of  the  common  ion  of  chromium.  Other  common  ion   of  chromium  include  chromium  of  oxidation  state  6  and  3

8 0
3 years ago
Read 2 more answers
Which element is most plentiful in Earth's crust?
dem82 [27]

Answer:

Oxygen is the most contain in earth but you asked in a,b,c and d. So I'll choice A. aluminium.

5 0
3 years ago
A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
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