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Alisiya [41]
3 years ago
8

Help please will be marked as brainliest if correct

Mathematics
2 answers:
Archy [21]3 years ago
8 0

Answer:

h = 10 bc 4.7 x 10 = 47

f = 36 bc 6 x 36 = 216

g = 3.5 bc 3.5 + 1.6 = 5.1

unlock number equation = f - g x h or 36 - 3.5 x 10

unlock number: 1

Alex73 [517]3 years ago
3 0

Answer:

Unlock number: 1

Step-by-step explanation:

<u>6f = 216</u>

6f/6 = 216/6

f = 36

<u>1.6 + g = 5.1</u>

5.1 - 1.6 = 3.5

g = 3.5

<u>4.7h = 47</u>

4.7h/4.7 = 47/4.7

h = 10

<u>f - g x h</u>

36 - 3.5 x 10

36 - 35

1

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The graph of this function is shifted downwards and the axis of symmetry remains x=1. Which function below the equation of the n
Natali5045456 [20]

Answer:

y=-x^{2}+2x

y=-x^{2}+2x-4

y=-x^{2}+2x-3

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

so

x=h

If a> 0 then the parabola open upward (vertex is a minimum)

If a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

y=-x^{2} +2x+3

The vertex is the point (1,4) ------> observing the graph

The axis of symmetry is x=1

If the graph of this function is shifted downwards and the axis of symmetry remains x=1

then

The x-coordinate of the vertex of the new graph must be equal to 1

The y-coordinate of the vertex of the new graph must be less than 4

The parabola of the new graph open downward

therefore

<u>Verify each case</u>

case a) y=-x^{2}+2x

Convert to vertex form

y=-(x^{2}-2x)

y-1=-(x^{2}-2x+1)

y-1=-(x-1)^{2}

y=-(x-1)^{2}+1

The vertex is (1,1)

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The function could be the equation of the new graph

case b) y=-x^{2}-2x+3

Convert to vertex form

y-3=-(x^{2}+2x)

y-3-1=-(x^{2}+2x+1)

y-4=-(x+1)^{2}

y=-(x+1)^{2}+4

The vertex is (-1,4)

therefore

The function cannot be the equation of the new graph

case c) y=-x^{2}+2x-4

Convert to vertex form

y+4=-(x^{2}-2x)

y+4-1=-(x^{2}-2x+1)

y+3=-(x-1)^{2}

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The vertex is (1,-3)

therefore

The function could be the equation of the new graph

case d) y=-x^{2}+2x+4

Convert to vertex form

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y-4-1=-(x^{2}-2x+1)

y-5=-(x-1)^{2}

y=-(x-1)^{2}+5

The vertex is (1,5)

therefore

The function cannot be the equation of the new graph

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Convert to vertex form

y+3=-(x^{2}-2x)

y+3-1=-(x^{2}-2x+1)

y+2=-(x-1)^{2}

y=-(x-1)^{2}-2

The vertex is (1,-2)

therefore

The function could be the equation of the new graph

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