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3 years ago

I need help with this, please

Mathematics

1 answer:

stellarik [79]3 years ago

4 0

none of the above

Step-by-step explanation:

SSS - only two legs are defined so this doesn't apply

SAS - the two legs of one triangle are not proportional to the legs of the other triangle.

AA - only one angle is defined to be congruent to the other (the rule requires two)

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Write the expression using exponents.<br><br>23 · y · y · y · y

Ostrovityanka [42]

Answer:

Exponent: 23y^4

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3 years ago

Please help

givi [52]

Answer: C) 4

==========================================================

Explanation:

Let's isolate t

-3 > -3t + 6

-3+3t > 6

3t > 6+3

3t > 9

t > 9/3

t > 3

This means any value can replace t such that it's larger than 3.

Something like t = 1/3 = 0.33 won't work since it's not larger than 3.

But something like t = 4 would work because it makes t > 3 true.

That's why choice C is the final answer.

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3 years ago

Solve each equation -8a - 1=-23

bagirrra123 [75]

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3 years ago

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What should be done first to evaluate the expression?<br> 6+8+ 4+ (4 x 5)2

mars1129 [50]

Answer: 40x+18

Step-by-step explanation:

4 0

3 years ago

H(x) = x + 1 k(x) = x - 2 (h + k)(2) =

barxatty [35]

$h(x) = x + 1$

$k(x) = x - 2$

_________________________________

$(h + k)(x) = h(x) + k(x)$

$(h + k)(x) = (x + 1) + (x - 2) \\$

$(h + k)(x) = x + 1 + x - 2$

$(h + k)(x) = 2x - 1$

$(h + k)(2) = 2(2) - 1$

$(h + k)(2) = 4 - 1$

$(h + k)(2) = 3$

_________________________________

And we're done.....♥️♥️♥️♥️♥️

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3 years ago