Please answer this question correctly please

Mathematics

1 answer:

STatiana [176]3 years ago

8 0

ANSWER: 40 deg.

EXPLANATION:
To find the measure of AC you multiply the corresponding central angle by 2 so (20*2).
BD is equivalent to AC; therefore, BD is 40.

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Estimate by rounding each number to the nearest hundredth and then subtract 360.727 - 89.852

kykrilka [37]

Hi there!

The correct answer for you is 270.88.

To round to the hundreth's place (.01), you need to take the number in the thousand's place (.001), and determine if the number needs to go up or down.

If the number in the thousand's place is greater than 4, then the number goes up.

360.727 --> This means that the hundreth's number goes up to 3.

If the number in the thousand's place is lesser than 5, then that number stays the same.

89.852 --> This means that the hundreth's number stays the same.

After you round, then just subtract:

360.73 - 89.85 = 270.88.

I hope this helps!
Brady

7 0

3 years ago

Which number should each side of the equation 45x=845x=8 be multiplied by to produce the equivalent equation of x = 10?

Scilla [17]

2nd or 3rd option I hope I narrowed it down

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this question, we have that:

$\pi = 0.21$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when $M = 0.03$ . So