Question

Can anyone solve these for me?

Answer 1

$\theta = 38^o \\\ tan(38^o) = \frac{x}{3}, x = 3tan(38^o), x\approx2.344 \\\ sin(38^o) = \frac{2.344}{y}, y = \frac{2.344}{sin(38^o)}, y \approx 3.807$Geometry Rule: SOH CAH TOA.
Sine = opposite over hypotenuse
Cosine = adjacent over hypotenuse
Tangent = opposite over hypotenuse
I won't solve all of these for you because I find that solving it on your own is an important step in learning to actually understand how this works.