You can solve a system with variables by:
1. Pick any two pairs of equations from the system.
2. Eliminate the same variable from each pair using the Addition/Subtraction method
3. Solve the system of the two new equations using the Addition/Subtraction method
4. Substitute the solution back into one of the original equations and solve for the third variable
5. check by plugging the solution into one of the other three equations
Hello,
A
quadratic trem= 4x²-4x²=0
linear terms=4x-x=3x
Constant term =1*(-1)=-1
y
quadratic trem= -15x²
linear terms=-15x -18x=-33x
Constant term =3*(-6)=-18
L= length= 1 1/2 yards
A= area= 3 1/2 yards^2
w= width
Area= length * width
plug in numbers you know
3 1/2= (1 1/2)(w)
convert to improper fractions
(3*2+1)/2= ((1*2+1)/2)(w)
7/2= 3/2w
divide both sides by 3/2
7/2 ÷ 3/2= w
to divide fractions, multiply by the reciprocal/inverse of 3/2
7/2 * 2/3= w
(7*2)/(2*3)= w
14/6= w
reduce by 2
7/3= width as improper fraction
OR
2 1/3= width as mixed fraction
ANSWER: The width should be 2 1/3 yards wide (or 7/3 yards wide).
Hope this helps! :)
3/5 of 180 is 108
180-108=72
she would have 72$ left
