Can anyone solve these for me?

Mathematics

1 answer:

alex41 [277]3 years ago

3 0

$\theta = 38^o
\\\ tan(38^o) = \frac{x}{3}, x = 3tan(38^o), x\approx2.344
\\\ sin(38^o) = \frac{2.344}{y}, y = \frac{2.344}{sin(38^o)}, y \approx 3.807$ Geometry Rule: SOH CAH TOA.
Sine = opposite over hypotenuse
Cosine = adjacent over hypotenuse
Tangent = opposite over hypotenuse
I won't solve all of these for you because I find that solving it on your own is an important step in learning to actually understand how this works.

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