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3 years ago

Yo can someone please help and fast PLEASE

Mathematics

1 answer:

Illusion [34]3 years ago

6 0

Answer:

It's incorrect because the equation is solve incorrectly the anwer is r= -4

Step-by-step explanation:

Add 4r4r to both sides.

-3r+9+4r=5

−3r+9+4r=5

2 Simplify -3r+9+4r−3r+9+4r to r+9r+9.

r+9=5

3 Subtract 99 from both sides.

r=5-9

r=5−9

4 Simplify 5-95−9 to -4−4.

r=-4

r=−4

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Step-by-step explanation:

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3 years ago

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Answer:

The complete question is defined in the attached file please find it.

Step-by-step explanation:

For question 1:

$\to 4-(3+1)^2 - 6\div 2 +4 \\\\\to 4-(4)^2 - 6\div 2 +4\\\\\to 4-16 - 3 +4\\\\\to 4-19 +4\\\\\to 4-15\\\\\to -11$

For question 2:

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$\to 3x^2(4x^3- 2x^2+7x -4) \\\\\to 12x^5- 6x^4+21x^3 -12x^2 \\\\$

For question 5:

$\to 6x^2+9x-7 \ \ \text{when} \ \ x=2\\\\\to 6(2)^2+9(2)-7 \\\\\to 6(4)+9(2)-7 \\\\\to 24+18-7 \\\\\to 24+11 \\\\\to 35$

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3 years ago

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4 years ago

Read 2 more answers

The weights of bags of peas are normally distributed with a mean of 13.50 ounces and a standard deviation of 1.06 ounces. Bags i

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Answer:

The most that a bag can weigh and not need to be repackaged is 15.355 ounces.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 13.50, \sigma = 1.06$

Bags in the upper 4% are too heavy and must be repackaged. What is the most that a bag can weigh and not need to be repackaged?

Bags in the upper 4% have a pvalue of 1-0.04 = 0.96. So the most that a bag can weight and not need to be repackaged is the value of X when Z has a pvalue of 0.9599. So this is X when $Z = 1.75$