Answer:
B) 3^-5 <em>(1 / 243)</em> and D) 2^5 x 6^-5 <em>(</em><em>1</em><em> </em><em>/</em><em> </em><em>2</em><em>4</em><em>3</em><em>)</em>
Step-by-step explanation:
3 to the negative 5th power as a fraction is
1 / 243.
2 to the power of 5 multiplied by 6 to the power of negative 5 also equals 1 / 243.
Both expressions are equivalent to 2^5 / 6^5 because they equal the same thing (1 / 243).
Answer:
12rf
Step-by-step explanation:
4 times 3 is 12 and r times f just becomes rf so you are correct.
Answer:
794.19 feet.
Step-by-step explanation:
Please find the attachment.
Let x be the distance helicopter needs to fly to be directly over the tower.
We have been given that a helicopter flying 3590 feet above ground spots the top of a 150-foot y'all cell phone tower at an angle of depression of 77°.
We can see from our attachment that helicopter, tower and angle of depression forms a right triangle.
As height of tower is 150 feet, so the vertical distance between helicopter and tower will be
feet.
We cab see from our attachment that the side with length 3590-150 feet is opposite and side x is adjacent side to 77 degree angle.
Since we know that tangent relates the opposite side of a right triangle to its adjacent side, so we will use tangent to find the length of x.

Upon substituting our given values in above formula we will get,




Therefore, the helicopter must fly approximately 794.19 feet to be directly over the tower.
True. A regular quadrilateral has 4 equal sides.
When two or more lines are <u>parallel</u> to each other, this implies that they do not meet even extending them till <em>infinity</em>. So the <em>statement</em> justifies the construction because only <em>one</em> line <u>through</u> point C can be constructed to be <u>parallel</u> to AB.
When a <u>parallel</u> line is constructed through a <em>point</em> to a given <em>line</em>, this is the only <u>parallel</u> line that can be <em>drawn</em> to the given line. <u>Parallel</u> lines are lines that will not meet at any point. Thus, only one <u>parallel</u> line can be constructed through a <em>point</em> not to a given <em>line</em>.
The construction of a line through C that is <u>parallel</u> to line AB is justified by the given <em>statement</em> in the <em>theorem </em>since this is the only <u>parallel</u> line to line AB that can be drawn <em>through</em> the point C. Any <em>other line</em> through C would <em>intersect</em> or <em>meet</em> line AB at a point when <u>extended,</u> thus would not be <u>parallel</u> to the given line.
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