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KengaRu [80]
3 years ago
14

A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force

has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.​
Physics
1 answer:
Sauron [17]3 years ago
4 0

Answer:

The acceleration is 2.448 meters per square second and is vertically upward.

Explanation:

The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:

\Sigma F = F - m\cdot g = m\cdot a (1)

Where:

F - Buoyant force, measured in newtons.

m - Mass of the plastic ball, measured in kilograms.

g - Gravitational acceleration, measured in meters per square second.

a - Net acceleration, measured in meters per square second.

If we know that F = 5\,N, m = 0.408\,kg and g = 9.807\,\frac{m}{s^{2}}, then the net acceleration of the plastic ball is:

a = \frac{F}{m} - g

a= 2.448\,\frac{m}{s^{2}}

The acceleration is 2.448 meters per square second and is vertically upward.

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A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 592 N. As the elevator la
gladu [14]

Answer:

<h2>a) 496N</h2><h2>b) 50.56kg</h2><h2>c) 1.90m/s²</h2>

Explanation:

According to newton's secomd law, ∑F = ma

∑F is the summation of the force acting on the body

m is the mass of the body

a is the acceleration

Given the normal force when the elevator starts N1 = 592N

Normal force after the elevator stopped N2 = 400N

When the elevator starts, its moves upward, the sum of force ∑F = Normal (N)force on the elevator - weight of the person( Fg)

When moving up;

N1 - Fg = ma

N1 = ma + Fg ...(1)

Stopping motion of the elevator occurs after the elevator has accelerates down. The sum of forces in this case will give;

N2 - Fg = -ma

N2 = -ma+Fg ...(2)

Adding equation 1 and 2 we will have;

N1+N2 = 2Fg

592N + 400N = 2Fg

992N 2Fg

Fg = 992/2

Fg = 496N

The weight of the person is 496N

<em>\b) To get the person mass, we will use the relationship Fg = mg</em>

g = 9.81m/s

496 = 9.81m

mass m = 496/9.81

mass = 50.56kg

c) To get the magnitude of acceleration of the elevator, we will subtract equation 1 from 2 to have;

N1-N2 = 2ma

592-400 = 2(50.56)a

192 = 101.12a

a = 192/101.12

a = 1.90m/s²

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4 years ago
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