sunlight, and the position of the earth
<span>If
a contour interval of a topographic map is 50 feet, there would be 3
contour lines drawn between sea level and an elevation of 175 feet.</span>
The number of protons, neutrons, and electrons in an atom can be determined from a set of simple rules. ... The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus.
The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
Answer:
Correct answer: (a) Ekmax = 1.3 · 10⁻¹⁹ J, (b) ε = 5 eV, (c) f = 1.21 · 10¹⁵ Hz
Explanation:
Given:
photon energy ε = 8 · 10⁻¹⁹ J
work function for metal Wf = 6.7 · 10⁻¹⁹ J
(a) Ekmax = ?
The Einstein equation for photo effect is:
ε = Wf + Ekmax ⇒ Ekmax = ε - Wf
Ekmax = 8 · 10⁻¹⁹ - 6.7 · 10⁻¹⁹ = 1.3 · 10⁻¹⁹ J
Ekmax = 1.3 · 10⁻¹⁹ J
(b) ε = ? eV
the relationship between 1 eV and 1 J is:
1 eV = 1.6 · 10⁻¹⁹ J
so the energy of one photon in eV equals:
ε = 8 · 10⁻¹⁹ J = 8 · 10⁻¹⁹ / 1.6 · 10⁻¹⁹ eV = 5 eV
ε = 5 eV
(c) f = ?
the energy of a single photon is calculated according to the formula:
ε = h · f
where is:
h = 6.62 · 10⁻³⁴ J s plank constant
and f frequency of each photon (electromagnetic radiation)
f = ε / h = 8 · 10⁻¹⁹ J / 6.62 · 10⁻³⁴ J s = 1.21 · 10¹⁵ s⁻¹ = 1.21 · 10¹⁵ Hz
f = 1.21 · 10¹⁵ Hz
God is with you!!!
