why is it more difficult to revolve a stone by tieing it in a longer string then by tieing it to a shorter string

1 answer:

6 0

Because it gives it more space to be able to move farther and faster which can change the speed in which you want it to go

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According to the formula for stopping distance, how many feet will it take you to stop, from 60 mph?

myrzilka [38]

Answer:

534 ft

Explanation:

given,

speed of the vehicle = 60 mph

1 mph = 0.447 m/s

60 mph = 60 x 0.447 = 26.82 m/s

stopping distance = ?

Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.

Reaction time of a common person = 1.5 s

taking coefficient of friction of the road = 0.3

using equation of stopping sight distance

S.D = RD + BD

RD is Reaction distance

RD = v t_r

RD = 26.82 x 1.5

RD = 40.23 m

BD is the braking distance

$BD = \dfrac{v^2}{2\mu g}$

$BD = \dfrac{26.82^2}{2\times 0.3\times 9.8}$

BD = 122.33 m

Stopping sight distance

SD = 40.23 + 122.33

SD = 162.56 m

1 m = 3.28 ft

162.56 m = 162.56 x 3.28

= 533.20 ft ≈ 534 ft

hence, the stopping distance will be equal to 534 ft

8 0

3 years ago

Of the solar radiation entering the atmosphere, about ___% reaches the surface directly as direct radiation.

strojnjashka [21]

Of the solar radiation entering the atmosphere, about 22.5% reaches the surface directly as direct radiation and is being absorbed. Thirty five percent of it is reflected back to the space. While 10.5% and 14.5% are scattered to the earth from the blue sky and from clouds, respectively. Also, 17.5 percent was being absorbed by the atmosphere. Thus leaving only 22.5% to be given directly to the Earth's surface. Also, another factor of this low value would be the transparency of the atmosphere. The atmosphere of the Earth has only an effective transparent to radiation from the sun of about .34 to .7 micrometer.

8 0

3 years ago

When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.6

Bezzdna [24]

Answer:

Distance between the charges, r = 0.8 meters

Explanation:

Given that,

Charge 1, $q_1=+8.4\ \mu C=+8.4\times 10^{-6}\ C$