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matrenka [14]
2 years ago
11

Joshua programs a robotic arm to place a block in a box by following the sequence of commands in the table. a 2-column table wit

h 4 rows. the first column labeled step has entries 1, 2, 3, 4. the second column labeled command has entries, grip block, lift block 10 centimeters, hold for 20 seconds, release block. during which step does the robotic arm do work on the block? step 1 step 2 step 3 step 4.
Physics
1 answer:
GarryVolchara [31]2 years ago
6 0

Step 2 does the robotic arm do work on the block. Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.

<h3>What is a robotic arm?</h3>

A robotic arm is a type of artificial arm that may be programmed to do tasks similar to those of a human arm.

The arm can be the sum of the mechanism or part of a larger robot. Joints connect the manipulator's linkages, allowing rotational or translational motion.

By following the directions in the table, Joshua programs a robotic arm to place a block in a box. a four-row, two-column table.

The items in the first column labeled step are 1, 2, 3, and 4. Grip block, elevate block 10 cm, hold for 20 seconds, release block are the items in the second column labeled command.

Step 2 does the robotic arm do work on the block.

Hence,step 2 is the correct answer.

To learn more about the robotic arm refer:

brainly.com/question/14768119

#SPJ1

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Answer:

8 seconds

Explanation:

power (P) is defined as the rate at which work is done.

power is measured in Watts (W) , when the work done is measured in Joules (J) and time in seconds

by the definition of power,

Power=\frac{work.done}{time.taken} \\ \\ time.taken=\frac{work.done}{power}\\=\frac{720J }{90W} \\ \\ =8 s

3 0
3 years ago
A motorcyclist changes the velocity of his bike from 20.0 meters/second to 35.0 meters/second under a constant acceleration of 4
Fiesta28 [93]
35-20 = 15m/s difference
15/4 = 3.75 seconds
4 0
3 years ago
Match the phrase with the term. How hard the blood pushes on the inside of the blood vessels is called . The total amount of blo
taurus [48]

Answer:

How hard the blood pushes on the inside of the blood vessels is called? BLOOD PRESSURE

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CARDIAC OUTPUT

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DILATE

How many times your heart beats in one minute is called ?

HEART RATE

The force that can put unhealthy tension on the heart as it is pumping is called ?

BLOOD PRESSURE

The amount of blood the heart pumps out in one beat is called?

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Explanation:

4 0
3 years ago
Two particles with masses 2m and 9m are moving toward each other along the x axis with the same initial speeds vi. Particle 2m i
s2008m [1.1K]

Answer:

The final speed for the mass 2m is v_{2y}=-1,51\ v_{i} and the final speed for the mass 9m is v_{1f} =0,85\ v_{i}.

The angle at which the particle 9m is scattered is \theta = -66,68^{o} with respect to the - y axis.

Explanation:

In an elastic collision the total linear momentum and the total kinetic energy is conserved.

<u>Conservation of linear momentum:</u>

Because the linear momentum is a vector quantity we consider the conservation of the components of momentum in the x and y axis.

The subindex 1 will refer to the particle 9m and the subindex 2 will refer to the particle 2m

\vec{p}=m\vec{v}

p_{xi} =p_{xf}

In the x axis before the collision we have

p_{xi}=9m\ v_{i} - 2m\ v_{i}

and after the collision we have that

p_{xf} =9m\ v_{1x}

In the y axis before the collision p_{yi} =0

after the collision we have that

p_{yf} =9m\ v_{1y} - 2m\ v_{2y}

so

p_{xi} =p_{xf} \\7m\ v_{i} =9m\ v_{1x}\Rightarrow v_{1x} =\frac{7}{9}\ v_{i}

then

p_{yi} =p_{yf} \\0=9m\ v_{1y} -2m\ v_{2y} \\v_{1y}=\frac{2}{9} \ v_{2y}

<u>Conservation of kinetic energy:</u>

\frac{1}{2}\ 9m\ v_{i} ^{2} +\frac{1}{2}\ 2m\ v_{i} ^{2}=\frac{1}{2}\ 9m\ v_{1f} ^{2} +\frac{1}{2}\ 2m\ v_{2f} ^{2}

so

\frac{11}{2}\ m\ v_{i} ^{2} =\frac{1}{2} \ 9m\ [(\frac{7}{9}) ^{2}\ v_{i} ^{2}+ (\frac{2}{9}) ^{2}\ v_{2y} ^{2}]+ m\ v_{2y} ^{2}

Putting in one side of the equation each speed we get

\frac{25}{9}\ m\ v_{i} ^{2} =\frac{11}{9}\ m\ v_{2y} ^{2}\\v_{2y} =-1,51\ v_{i}

We know that the particle 2m travels in the -y axis because it was stated in the question.

Now we can get the y component of the  speed of the 9m particle:

v_{1y} =\frac{2}{9}\ v_{2y} \\v_{1y} =-0,335\ v_{i}

the magnitude of the final speed of the particle 9m is

v_{1f} =\sqrt{v_{1x} ^{2}+v_{1y} ^{2} }

v_{1f} =\sqrt{(\frac{7}{9}) ^{2}\ v_{i} ^{2}+(-0,335)^{2}\ v_{i} ^{2} }\Rightarrow \ v_{1f} =0,85\ v_{i}

The tangent that the speed of the particle 9m makes with the -y axis is

tan(\theta)=\frac{v_{1x} }{v_{1y}} =-2,321 \Rightarrow\theta=-66,68^{o}

As a vector the speed of the particle 9m is:

\vec{v_{1f} }=\frac{7}{9} v_{i} \hat{x}-0,335\ v_{i}\ \hat{y}

As a vector the speed of the particle 2m is:

\vec{v_{2f} }=-1,51\ v_{i}\ \hat{y}

8 0
3 years ago
How many electrons does it take to make up 4.33 C of charge?
Dovator [93]

Answer:

Number of electrons, n=2.7\times 10^{19}

Explanation:

It is given that,

Charge, q = 4.33 C

We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :

q=ne

n = number of electrons

e = electron's charge

n=\dfrac{q}{e}

n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}

n=2.7\times 10^{19}

So, the number of electrons are 2.7\times 10^{19} Hence, this is the required solution.  

7 0
2 years ago
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