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Zanzabum
3 years ago
8

An artist printed 1026 greeting cards and plans to package them for distribution. How many can be put into each box so theres no

greeting cards left over?
A.)15.
B.) 18
C.) 24.
D.) 12​
Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

B

Step-by-step explanation:

18 is the only number given that can be divided without having a remainder or decimal.

1026 ÷ 18 = 57

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Given the coordinates of A(3, 6), B(5, 2), and C(9, 4), which coordinates for D make ABCD a square?
tankabanditka [31]

Answer:

(7,8)

Step-by-step explanation:

6 0
3 years ago
On a winter day in Alaska, the temperature at noon was -0.6°C. From noon to 3:00, the temperature increased by 1.2°C. From 3:00
vazorg [7]
The expression is -6 + 1.2 + -0.4 + -0.6


7 0
3 years ago
What are the zeros of this function? Circle them on the graph.
Rashid [163]

Given:

The graph of a function.

To find:

The zeros of this function on the graph.

Solution:

We know that, zeros are the values at which the values of the function is 0. It means, the points where the graph of function intersect the x-axis are know as zeros of the function.

From the given graph it is clear that, the graph intersect the x-axis at two points.

Therefore, the marked points on the below graph are the zeros of the function.

8 0
3 years ago
Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Need help asap
sergeinik [125]

GTA LITE V2 BY WITLOPPELZGAMING

4 0
3 years ago
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