<h3>volume =603.19 cm cube</h3>
Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer: it is in absolute value form, so when you take it out the signs would change to 7 + 42 = 49
Step-by-step explanation:
7 x² + 7 y² - 28 x + 42 y - 35 = 0 /: 7
x² + y² - 4 x + 6 y - 5 = 0
( x² - 4 x + 4 ) + ( y² + 6 y + 9 ) - 4 - 9 - 5 = 0
The equation in the standard form is:
( x - 2 )² + ( y + 3 )² = 18
The center is at the point ( 2, - 3 ).
Its radius is: √18 = 3√2 units.
