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Rufina [12.5K]
3 years ago
5

The graph shows the number of flowers that can be pollinated as the number of bees increase. What is the unit rate?

Mathematics
1 answer:
dybincka [34]3 years ago
5 0

Answer:

6

Step-by-step explanation:

Hope that helps

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Y+3y-2=3, the linear equation will be correct but, if the answer what is the 3/4 70 of the number, perimeter, and value of x? wo
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I thought this would be simple, as I'm familiar with algebra and not really "The constant of proportionality," but I will do my best.

So this said "Constant of proportionality," is referring to basically the answers for the equation when X equals certain numbers.

Make a table of different answers when you plug in X and you get the 'Constant of proportionality.'

y = 2.5x + 3
y = 2.5(1) + 3
y = 2.5 + 3
y = 5.5

Since we plugged in 1 for X and got 5.5 for Y, our input and output is (1, 5.5)

Replace X for a different value, and you will get a bunch of different numbers that will in essence be your function inputs and outputs.  Make a table of these and you have your answer.

EXAMPLE - 
-= x =-   -= y =-
-= 1 =-   -= 5.5 =-
-= 2 =-   -= 8 =-
-= 3 =-   -= 11.5 =-
-= 4 =-   -= 13 =-


So there you have it.  I hope this helps!  If you have any further questions, don't hesitate to ask.
3 0
2 years ago
1234567791234556677889
Lapatulllka [165]
372819388338822814738288919147477483822 okay i guess
3 0
2 years ago
Read 2 more answers
Graph Y= 1/3x {If someone could help me on this I would really appreciate it}
gizmo_the_mogwai [7]
Y=1/3x while m=0................

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7 0
3 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
3 years ago
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