The answer is 4 m/s.
In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).
The relation of speed (v), distance (d), and time (t) can be expressed as:
v = d/t
We need to calculate the speed of the second 5 seconds of the travel:
d = 20 m (total 30 meters - first 10 meters)
t = 5 s (time from t = 5 seconds to t = 10 seconds)
Thus:
v = 20m / 5s = 4 m/s
Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
Hey there!
3 + 67 = 70,
so your answer will be:
x = 3
Hope this helps!
Have a great day (:
Answer:
The consecutive numbers are 62 and 63
Step-by-step explanation:
Let the larger number be represented by x and the smaller number by y,
Provided they are consecutive numbers;
--- Equation 1
From the question; we have that
--- Equation 2
Required
Find x and y
Multiply both sides of equation 2 by 14


---- Equation 3
Substitute y + 1 for x in equation 2

Open bracket

Collect like terms



So,


Hence, the consecutive numbers are 62 and 63

Substitute
, so that
, and

which is separable as

Integrate both sides with respect to
. For the integral on the left, first split into partial fractions:



Solve for
:






Replace
and solve for
:


Now use the given initial condition to solve for
:

so that the particular solution is
