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zloy xaker [14]
3 years ago
12

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Mathematics
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

$12.30

Step-by-step explanation:

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Find the midpoint of the segment with the following endpoints.<br> (-3,8) and (-8, 2)
Marrrta [24]

Answer:

Coordinates of the midpoint are (-5.5, 5)

5 0
3 years ago
Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
3 years ago
7 divided by 20 is what answers
Montano1993 [528]
Hello! 

The Correct Answer to this is that <span>7 divided by 20 or 7/20 equals:

"7/20 = 0.35"

</span>Explanation:

Since you are trying to find equivalent values for 7/20, you can make two proportions and set them equal to each other. The following states that "7 out of 20 is equal to some amount out of 100."

<span><span>7/20</span>=<span>x/100</span></span>

Solve by cross multiplying:

<span>20x=700</span>

Divide both sides by 20 to isolate x:

<span>x=35</span><span> Therefore, </span><span><span>7/20</span>=<span>35/100</span></span><span>. This is the same as saying 35%, since by definition "per" means out of, and "cent" means hundred. To make it into a decimal just move the decimal place two digits to the left, such that 35.00 becomes 0.35, and 100.00 becomes 1. Then it is simply </span><span>0.35/1</span><span>, or 0.35</span>

<span>
Hope this Helps! Have A Wonderful Day! :)</span>
5 0
3 years ago
Read 2 more answers
What is a square root of (a-b)^2
Bess [88]
Hello,

\sqrt{(a-b)^2}=|a-b| \\ &#10;= a-b\  if\  a \ \textgreater\ b \\&#10;=b-a\  if\  a\ \textless \ b
4 0
3 years ago
53.58 is 47 percent of what?
I am Lyosha [343]

Answer:114

Sorry

Step-by-step explanation:

8 0
3 years ago
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