Enter the output values (Y) with the given function and input values (X). y = 3x

The computer lab at a high school ordered 26 packages of Cra. There were 50 CDs in each packages. How many CDs did the computer

astra-53 [7]

Hey You!

To solve this question, we must use multiplication:

26 × 50 = 1,300

The computer ordered 1,300 CDs.

5 0

3 years ago

Mr. Erickson will be living in the forest

aliina [53]

$\huge{\boxed{60\ \text{ft}^{3}}}$

We will assume the tent is in the shape of a triangular prism.

The volume of a triangular prism can be found with the following formula, where $b$ is the width at the base, $h$ is the height, and $l$ is the length.

$V=\frac{1}{2}bhl$

Substitute in the known values.

$V=\frac{1}{2}*5*3*8$

Simplify — use multiplication.

$V=\frac{5}{2}*3*8$

$V=\frac{15}{2}*8$

$V=\frac{120}{2}$

Simplify — use division.

$V=\large{\boxed{60\ \text{ft}^{3}}}$

The volume — or in this case, the amount of living space — is $60\ \text{cubic feet}$ .

7 0

3 years ago

A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent

siniylev [52]

Answer:

(a) P (p' > 0.25) = 0.

(b) P (0.15 < p' < 0.20) = 0.7784.

(c) P (133 < X < 171) = 0.2205

Step-by-step explanation:

Let p = proportion of business trip that were for internal company visit.

It is provided that 19% responded that it was for an internal company visit, i.e.

p = 0.19.

A sample of n = 950 business travelers are randomly selected.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

Thus, the distribution of $\hat p$ is N (μ = 0.19, σ = 0.013).

(a)

Compute the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (p' > 0.25) = P (Z > 4.62) = 0

*Use a z-table for the probability.

Thus, the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.

(b)

Compute the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit as follows:

P (0.15 < p' < 0.20) = P (-3.08 < Z < 0.77)

= P (Z < 0.77) - P (Z < -3.08)

= 0.7794 - 0.0010

= 0.7784

*Use a z-table for the probability.

Thus, the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.7784.

(c)

Compute the proportion of X = 133 and X = 171 as follows:

p' = 133/950 = 0.14

p' = 171/950 = 0.18

Compute the value of P (0.14 < p' < 0.20) as follows:

P (0.14 < p' < 0.18) = P (-3.85< Z < -0.77)

= P (Z < -0.77) - P (Z < -3.85)

= 0.2206- 0.0001

= 0.2205

*Use a z-table for the probability.

Thus, the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit is 0.2205.

7 0

3 years ago

Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their sm

Ksivusya [100]

Answer:

d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Step-by-step explanation:

Confidence interval:

x% confidence

Of a sample

Between a and b.

Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.

In this question:

I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.

Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.

3 0

4 years ago

Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th

Ilya [14]

Answer:

13 1/3 and 6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' = 40x - 3x^2 = 0 for maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and 6 2/3.

3 0

3 years ago

Enter the output values (Y) with the given function and input values (X). y = 3x - 2