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kkurt [141]
3 years ago
6

Find the measure of 7

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

96° because it is congruent to angle 7

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Pls help with this math
eimsori [14]
The answer is B) 27

If explanation is needed, let me know
5 0
4 years ago
Read 2 more answers
Write the following in slope intercept form:
BabaBlast [244]
To change it into slope intercept (y=mx+b) you just replace the inequality with an equality and isolate y

x<=2:
x=2=y-> y=2 or y=2+0x

2x-3y>=4:
2x-3y=4
2x-4=3y
(2/3)x-(4/3))=y
y=(2/3)x-(4/3)

x+y>0:
x+y=0
y=-x or y=-x+0
7 0
4 years ago
In the 75th Congress (1937−1939) there were in the Senate 75 Democrats, 17 Republicans, and 4 members of other parties. Suppose
ira [324]

Answer:

42 Democrats members

12 Republicans members

2 other parties members

Step-by-step explanation:

We know that there are a total number of voters of

  • 75 (democrats)+17 (Republicans)+ 4( Other parties)=  96 voters

And we know that the bill has passed with 16 nore votes in favor that against, so let's calculate how many votes in favor of the bill we have:

  • 96 Votes = F (votes in Favor)+ A (votes against)

also: F= A+16= A = F-16, so:

  • 96= F+A= F+F-16 => F= 56 votes in favor of the bill

Thos 56 votes are the sum of the votes in favor from all the parties:

56 = D (votes in favor of democrats)+R ((votes in favor of Republicans)+OTH (votes in favor of other parties)

=> 56= D+R+OTH (A)

also democrat's votes in favor are three times the sum of non-democrat's votes in favor:

  • D= 3*( R+OTH) => OTH= D/3-R

and we have 30 more democrats thar republicans voting in favor:

  • D= R+30 => R=D-30

if we replace in the (A) formula:

56 = D+R+OTH => 56= D+D-30+D/3-D+30 =>

  • 56=4/3*D => D=42 (DEMOCRATS VOTES IN FAVOR)
  • R= D-30 => R= 12 (REPUBLICAN VOTES IN FAVOR)
  • OTH= D/3-R= 14-12= 2 (OTHER PARTIE'S VOTES IN FAVOR)

5 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
PLEASE HELP HURRY I’ll GIVE YOU 50 POINTS 8. Pentagon ABCDE is rotated 90 degrees clockwise about the origin to form pentagon A'
tatiyna

Answer:

URRFGQIYRVFBQY3HFVBUEWBDI2O3NDOUQ2BOF4Q

Step-by-step explanation:

6 0
3 years ago
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