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Vera_Pavlovna [14]
3 years ago
5

Plsssssssssssssssshelppppppppppppppppppppppppppppppppppppp

Mathematics
2 answers:
scZoUnD [109]3 years ago
8 0

Answer:

Help with what?

tino4ka555 [31]3 years ago
4 0

ummmmmmmmmmmmmmmmmmmmmmmmmm?mmmmmmmmmmmmmmmm?mmmmmmmmmmmmm withhhhhhhhhhhhhhhhh whatttttttttttttttttt

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A square has a side of 6.25 feet. What is the area in square feet? Round to the correct significant digits.
dem82 [27]
The answer for this question, to the correct significant digits, would be 39 feet squared. This can be worked out in the following way: S=a*a ft^2S=6.25*6.25S=39.0625?39.1 9and then round this up to find the answer of 39 square feet)
4 0
3 years ago
Simplify the radical expression.
Ber [7]

\bf \sqrt[4]{625x^{12}y^8}~~ \begin{cases} 625=&5\cdot 5\cdot 5\cdot 5\\ &5^4\\ x^{12}=&x^{3\cdot 4}\\ &(x^3)^4\\ y^8=&y^{2\cdot 4}\\ &(y^2)^4 \end{cases}\implies \pm\sqrt[4]{5^4(x^3)^4(y^2)^4}\implies \begin{array}{llll} \pm5x^3y^2\\\\ 5|x^3|y^2\\\\ |5x^3y^2| \end{array}

8 0
3 years ago
What is the radius of a circle with an area of 50.24 cubic inches? Use 3.14 for pi. Enter your answer in the box.
miss Akunina [59]

Answer:

r=4

Step-by-step explanation:

Area of a circle is

A = pi* r^2

We know the area and 3.14 = pi

50.24 = 3.14 * r^2

Divide each side by 3.14

50.24/3.14 =3.14 /3.14 *r^2

16 = r^2

Take the square root of each side

sqrt(16) = sqrt(r^2)

4 =r

3 0
3 years ago
Rita, Tony, and Deon have a total of $86 in their wallets. Rita has $ 10 less than Tony. Deon has 2 times what Rita has. How muc
8090 [49]
29-10 = 19
19(2) = 38
38+19+29=86
8 0
3 years ago
Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th
Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0

5 0
3 years ago
Read 2 more answers
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