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EastWind [94]
3 years ago
8

2 to the power of 46 is how many times as many as 2 to the power of 42

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

16

Step-by-step explanation:

bagirrra123 [75]3 years ago
5 0

Answer:

2⁴⁶ is 2⁻⁴ times as many as 2⁴²

Step-by-step explanation:

Given;

2 to the power of 46 = 2⁴⁶

2 to the power of 42 = 2⁴²

Let the number of times = y

2⁴⁶y = 2⁴²

divide both side of the equation by  2⁴⁶

\frac{2^{46}y}{2^{46}} = \frac{2^{42}}{2^{46}} \\\\y = 2^{42-46}\\\\y = 2^{-4}

Therefore, 2  to the power of 46 is 2 to the power -4 times as many as 2 to the power of 42. (i.e 2⁴⁶ is 2⁻⁴ times as many as 2⁴²)

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HELPPP
Rudiy27

Formula: A = 2wl + 2lh + 2hw

So... : A = 2(4x8) + 2(8x3) + 2(3x4)

         A = 2(32)   + 2(24)   + 2(12)

         A = 64 + 48 + 24

<u>Answer: A = 136</u> (add them all up)

Hope this helps!!!

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8 0
3 years ago
Which statement correctly describes the diagram?
Komok [63]

Answer:

option 2

Step-by-step explanation:

6 0
3 years ago
The amount that Jimmy paid for his meals the four days, $6.45, $21.38, $1.99, $7.99, $16, $0, $7.99, $18.95, $4.30, $10.35, $18.
ella [17]

Answer:

$7.99

Step-by-step explanation:

Arrange numbers in numerical order: $0, $1.99, $4.30, $6.45, $7.99, $7.99, $10.35, $16, $18.20, $18.95, $21.38.

Count how many numbers you have, 11.

11 is an odd number so, the number in the middle of the data set is the median.

Final answer: $7.99 is the median.

7 0
2 years ago
Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 29% each week. The following function represents
Dmitry [639]

Answer:

Option A. f(x)=86[1.04]^{x} ; grows approximately at a rate of 0.4% daily

Step-by-step explanation:

we have

f(x)=86(1.29)^{x}

where

f(x) the number of weeds in the garden

x ----> the number of weeks

Calculate how quickly the weeds grow each day

Remember that a week is equal to seven days

so

f(x)=86(1.29)^{\frac{x}{7}}

Using the law of exponents

b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x

so

f(x)=86[(1.29)^{\frac{1}{7}}]^{x}

f(x)=86[1.04]^{x}

therefore

The rate is approximately

1.04=1+r

r=1.04-1=0.04=4% daily

8 0
3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

8 0
3 years ago
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