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Over [174]
3 years ago
15

-0.6w=2.4 Please answer Hggjigj

Mathematics
2 answers:
SashulF [63]3 years ago
8 0

Final Answer: w = -4

Steps/Reasons/Explanation:

Question: Solve -0.6w = 2.4.

<u>Step 1</u>: Divide both sides by -0.6.

w = -\frac{2.4}{0.6}

<u>Step 2</u>: Simplify \frac{2.4}{0.6} to 4.

w = -4

~I hope I helped you :)~

Tom [10]3 years ago
4 0

Answer: 3

Step-by-step explanation:

-0.6/(-0.6)=2.4+(-0.6)

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QUICK!!<br><br> Which equation represents the relationship shown in the graph??
Dmitriy789 [7]

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y=1/2x

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Sara is renting a car for x amount of days. To rent the car she must pay an initial fee of $130 and then $17 for each day. If sa
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3 years ago
a student walks 50m on a bearing 0.25 degrees and then 200m due east how far is she from her starting point.​
Inessa05 [86]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

A_x=50cos(89.75) so

A_x=.22

B_x=200cos(0) so

B_x=200 and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

C_x=200 (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

A_y=50sin(89.75) so

A_y=50 (which I'm counting as 2 sig fig's)

B_y=200sin(0) so

B_y=0 and we need to add those results together.

C_y=50

Now for the resultant magnitude:

C_{mag}=\sqrt{(200)^2+(50)^2}  and that gives us a final magnitude of

C_{mag}=206 m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

tan^{-1}(\frac{50}{200})=14

The girl is 206 meters from her starting point at an angle of 14 degrees

4 0
3 years ago
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