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Aleks [24]
3 years ago
12

Samuel, Martín y Santiago salen a montar bicicleta de Cali hacia Palmira. La distancia entre Cali y Palmira es de 29.3 KM. En la

siguiente tabla se muestra los km que lograron realizar cada uno. Samuel izo 178/8 km , martin 21 3/4 km y santiago 21 5/12 ¿Quien recorrio mas distancia? ¿Cuantos km les falto a cada uno para llegar a palmira? ¿en promedio cuantos km recorrieron entre los 3 amigos? ¿¿Cuántos kilometros recorrió más Martín que Santiago? AYUDDAAAAAAAAaaaaaaa
Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

a) Martín recorrió más distancia, b) A Samuel, Martín y Santiago les falta 7.05, 7.55 y 7.883 kilómetros, respectivamente, c) La distancia recorrida promedio es 21.889 kilómetros, d) Martín recorrió 0.333 kilómetros más que Santiago.

Step-by-step explanation:

a) En primer lugar, convertimos la distancia recorrida por cada persona a su forma decimal:

Samuel

\frac{178}{8}\,km = 22.25\,km

Martin

21\,km + \frac{3}{4}\,km = 21.75\,km

Santiago

21\,km + \frac{5}{12}\,km = 21.417\,km

Como puede apreciarse, Martín recorrió más distancia.

b) La distancia faltante es igual a la sustracción de la distancia recorrida por la persona a la distancia total:

Samuel

x = 29.3\,km -22.25\,km

x = 7.05\,km

Martin

x = 29.3\,km - 21.75\,km

x = 7.55\,cm

Santiago

x = 29.3\,km - 21.417\,km

x = 7.883\,km

A Samuel, Martín y Santiago les falta 7.05, 7.55 y 7.883 kilómetros, respectivamente.

c) La distancia recorrida promedio se obtiene sumando las distancias recorridas de las tres personas y dividiendo el resultado por la cantidad de personas:

\bar{x} = \frac{22.5\,km + 21.75\,km + 21.417\,km}{3}

\bar x = 21.889\,km

La distancia recorrida promedio es 21.889 kilómetros.

d) Esta diferencia se encuentra a restar la distancia recorrida por Santiago a la distancia recorrida por Martín:

x = 21.75\,km - 21.417\,km

x = 0.333\,km

Martín recorrió 0.333 kilómetros más que Santiago.

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2 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
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Answer with explanation:

→Number of Integers from 1 to 100

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(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

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(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

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Maksim231197 [3]

Answer:

y = -17/2

Step-by-step explanation:

Substitute with the givens.

30= 8(8) + 4y.

Multiply parentheses.

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Divide each side by 4.

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hope that is right!

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