All categories

2 years ago

Find the measure of the side indicated. Round to the nearest tenth.

Mathematics

1 answer:

Alex2 years ago

6 0

Answer: x=1.2

Why?:
This is a 90-60-30 triangle
The sides of 90-60-30 triangle are: 2, square root of 3, 1

2.4/2 = x/1
2.4/2=2x/2

1.2=x

Hope this’ll help

You might be interested in

-4 < y + 2 < -2 solve for the inequality

Kitty [74]

Answer:

-6<y<-4

Step-by-step explanation:

-4<y+2<-2

-4-2<y+2-2<-2-2

-6<y<-4

6 0

2 years ago

. . ’ ‘ V v : c v » L ‘ 7 . -.z > " , ’ > r - ’ » ‘ - _ _ _ V g » ,, : 3x + 3 arr ’ ’ 2x + 4

Masteriza [31]

Parallel lines have the same slope.

'a' is the only choice that has the same slope (-5/4)
as the line in the question.

8 0

3 years ago

Please help with 15, 17 and 19

Irina-Kira [14]

Given:

15. $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

17. $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

19. $2^{\log_2100}$

To find:

The values of the given logarithms by using the properties of logarithms.

Solution:

15. We have,

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$

Using property of logarithms, we get

$\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)=1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{1}{2}}\left(\dfrac{1}{2}\right)$ is 1.

17. We have,

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$

Using properties of logarithms, we get

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-\log_{\frac{3}{4}}\left(\dfrac{3}{4}\right)$ $[\because \log_a\dfrac{m}{n}=-\log_a\dfrac{n}{m}]$

$\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)=-1$ $[\because \log_aa=1]$

Therefore, the value of $\log_{\frac{3}{4}}\left(\dfrac{4}{3}\right)$ is -1.

19. We have,

$2^{\log_2100}$

Using property of logarithms, we get

$2^{\log_2100}=100$ $[\because a^{\log_ax}=x]$

Therefore, the value of $2^{\log_2100}$ is 100.

6 0

3 years ago

Plz help with the math question

vampirchik [111]

Answer:

the answer is 20

8 0

3 years ago

Plzzzz help!! If you can thank you so much!

yawa3891 [41]

Answer:

233.5

Step-by-step explanation

5 0

3 years ago