All categories

3 years ago

Solve for c: 6/15=2/c

Mathematics

2 answers:

lions [1.4K]3 years ago

8 0

6/15=2/c

6/15=2/5

Solve for c:

2/5=2/c

2/5*1/2=2/c*1/2

2/10=c

1/5=c

Xelga [282]3 years ago

6 0

6/15 = 2/c
6/3 = 2, therefore you must divide 15 by 3 to get 5. c = 5
6/15 = 2/5

You might be interested in

Which number line correctly shows 1. 5 + 2. 5? A number line going from 0 to 6. 5 in increments of 0. 5. An arrow goes from 0 to

Usimov [2.4K]

So we want to see which number line shows the sum 1.5 + 2.5. We will see that the correct option is "An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

So the number line usually starts at 0 and goes to the first number, 1.5 in this case.

Then, it moves accordingly to the second number, 2.5 (so it will move 2.5 units to the right)

So the number line should start at 0 and move to the right until it meets 1.5 + 2.5 = 4.

From the options, the only that is correct is:

"An arrow goes from 0 to 1. 5 and from 1. 5 to 4"

If you want to learn more about number lines, you can read:

brainly.com/question/10851163

6 0

2 years ago

South School has a circular pattern on the playground that has a radius of 6 feet. Find a. the circumference of the pattern and

katrin [286]

Answer:

Circumference: 37.68

Area: 113.04

Step-by-step explanation:

the formula to find the circumference is 2 x 3.14 x r

r is the radius so you plug in 6 for that

2 x 3.14 x 6 = 37.68

the formula to find the area of a circle is 3.14 x r ²

r is still the radius so you plug in 6 for that

3.14 x 6² = 113.04

6 0

3 years ago

Pls help …. Need it immediately ….

Leno4ka [110]

The answer is 10.73 years.

Here, the formula we can use is :

$\boxed {Children = \frac{Boys+Girls}{2}}$ (for the average)

Substitute the values mentioned in the question.

10.54 = (10.35 + Girls)/2

21.08 = 10.35 + Girls

Girls = 10.73 years

3 0

2 years ago

The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

$x+y=5600...(1)$

$y=5600-x...(1)$

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be $40x$ and cost of y end-zone tickets would be $20y$ .

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

$40x+20y=134000...(2)$

Upon substituting equation (1) in equation (2), we will get:

$40x+20(5600-x)=134000$

$40x+112000-20x=134000$

$20x+112000=134000$

$20x+112000-112000=134000-112000$

$20x=22000$

$\frac{20x}{20}=\frac{22000}{20}$

$x=1100$

Therefore, 1100 field side tickets were sold.

Upon substituting $x=1100$ in equation (1), we will get:

$y=5600-1100$

$y=4500$

Therefore, 4500 end-zone tickets were sold.

3 0

3 years ago

What is the area of the figure?

Bad White [126]

20m ^2

Explanation:
The top part be be cut into 2 2•2 triangles. A = 4 for both of them
And the rest is a 4•4 square, so A = 16.
4 + 16 = 20

Hope this helps!

5 0

3 years ago