Answer: -1/5
Step-by-step explanation:
14/20 - 81/90=
7/10-9/10= ==> 10 is the GCF of 20 and 90
(7-9)/10=
-2/10=-1/5
28/8 = 3 remainder 4 so 3 4/8(fraction) or 3 1/2
You would want to divide the minutes to the songs so you can find out how long one song is, but sense there was a remainder you could turn it into a fraction or you could keep diving. In this case you would want to stop. To find the fraction here is a formula the divisor is the denominator, the numerator is the remainder and the whole number is the number you get that is behind the remainder
C. f(x) = – 2 cos 6x + 1
Start by determining the amplitude. Since we've deduced the amplitude is 2, the equation can include either a positive or negative 2 (since amplitude measures absolute value).
Next is the period. The equation for period P is P = (2pi)/b. If P is pi/3, then
pi/3 = (2pi)/b. Thus your b value should be 6.
Finally, the midline would be given by + 1 since adding a unit shifts the function upwards. This means that instead of the highest y value being 2 and the lowest -2, instead you'd have values of 3 and -1.
(3 – 1)/2 = 1 (midpoint theory).
Answer:
+5 is greater that -5 and is also a opposite integer.
Although the formula looks involved, the key here is looking to see where the information goes.
We are given all the pieces but need to convert mph to ft/s to use the formula. Let's do it with 1 mph so that we have a ratio to use. We and solve a unit conversion problem.
That ratio tells us that 1 mph is 1.466666 ft/s. Now we solve two proportions.
1 mph / 1.466666 feet per second = 60 mph / x feet per second.
1x = (60)(1.466666)
So x = 88 feet per second.
Next, We repeat for 24 mph.
1 mph / 1.46666 feet per second = 24 mph / x feet per second.
1x = (1.4666666)(24)
x = 35.2 feet per second
Now we have the found appropriate V₁ and V₂. V₁ > V₂, so V₁ is 88 ft/s and V₂ is 35.2 ft/s. The problem tells us θ = 2.3 degrees, K₁ = .4 and K₂ = .06. The rest of the problem is calculator work. Start by substituting our degree measure of 2.3 degrees and the given values in the problem for V₁, V₂, K₁, and K₂
![D = \frac{1.05[(88)^{2}-(35.2)^{2}]}{64.4(.4+.06 + (sin 2.3))}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.05%5B%2888%29%5E%7B2%7D-%2835.2%29%5E%7B2%7D%5D%7D%7B64.4%28.4%2B.06%20%2B%20%28sin%202.3%29%29%7D)
![D = \frac{1.05[(7744-1239.04]}{64.4(.46 + (sin 2.3))}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.05%5B%287744-1239.04%5D%7D%7B64.4%28.46%20%2B%20%28sin%202.3%29%29%7D)
D = 6830.208 / 32.208372
D = 212.0631 = 212 (to the nearest foot)
Thus the car needs 212 feet to stop.
