Answer:
A=-2.5x+45
Step-by-step explanation:
We have been given that a circle of a certain radius has an area which is numerically 5 times the value of the circumference. We are asked to find the radius of the circle.
We know that area of circle with a radius of r units is 
.
We know that circumference of a circle is 
.
5 times the value of circumference would be 
.
Now we will equate 5 times circumference with area as:
Let us solve for r.
Therefore, the radius of the circle would be 10 units.
Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
You could find this by going and doing:
<span>9: 9,18,27,36,45,54,63,72...
12:12,24,36,48,60,72...
</span>36 is the first # that pops up so you could do 36 as a common denominator
