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Reika [66]
3 years ago
6

Polly is comparing the cost of cell phone services. The phone she wants costs $899 at BT&T Cellular, and the unlimited calli

ng plan through their carrier would cost $2 per day. At Revizon Electronics, Polly could purchase the same phone for $799 and also get an unlimited calling plan for $3 per day. After some number of days, the two options would end up having the same total cost. What would the total cost be? How long would that take?
Mathematics
1 answer:
natima [27]3 years ago
5 0

Answer:

The total cost = $1,099

It would take 100 days

Step-by-step explanation:

Let

x = number of days

Cost of BT&T Cellular = 899 + 2x

Cost of Revizon Electronics = 799 + 3x

Equate the cost of both cell phone services.

899 + 2x = 799 + 3x

899 - 799 = 3x - 2x

100 = x

x = number of days = 100 days

Cost of BT&T Cellular = 899 + 2x

= 899 + 2(100)

= 899 + 200

= $1,099

Cost of Revizon Electronics = 799 + 3x

= 799 + 3(100)

= 799 + 300

= $1,099

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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

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Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

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a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

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For real roots the solution is given by:

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For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

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r_1_,_2=0\pm \sqrt{-1} =\pm i

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x'(t)=-c_1sin(t)+c_2cos(t)

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And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

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Step-by-step explanation:

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Answer:

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