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Rudik [331]
2 years ago
10

Find the distance between Brisbane and

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
5 0

Answer:

30 miles

Step-by-step explanation:

So since we know the scale of the map (3 in : 15 mi) we will just have to find out how much 3 inches fits into 6 inches and then multiply the result by 15 miles. So we do the following steps.......

(\frac{6}{3} )15 = (2)(15) = 30

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How would I write that translation rule (right 2, down 10)
Nady [450]

Answer: (2, -10)

Down and left are negative right and up are positive.

7 0
2 years ago
If < A and < B form a linear pair, and < A = x - 13 degrees, and < B = x + 7 degrees, then find x. Select one: a. 12
Andreas93 [3]

The correct value of "x" will be "93".

According to the question,

  • A linear pair of sum to 180°,

then

→ x-13+x+7=180

→             2x -6=180

By adding "6" both sides of the equation, we get

→       2x-6+6=180-6

→                   2x=186

→                     x = \frac{186}{2}

→                     x = 93

Thus "option d" is the right answer.  

Learn more:

brainly.com/question/19152299

8 0
2 years ago
Trevor has an investment worth $6,774.50. He made his only deposit in it 22 years ago. Given that the investment yields 2.7% sim
OleMash [197]
My initial answer was $2750.45, and I will show you my calculations.

Calc : 6774.5 ÷ 100 = 67.745
67.745 × 2.7 = 182.9115
182.9115 × 22 = 4024.053
6774.5 - 4024.053 = 2750.45

= $2750.45

At first I thought this was correct, but after studying my answer I realise that the amount of interest would rise as the amount of money went up, therefore my calculations are very wrong. If I work out the answer, I will get back to you, but the calculation is more complicated than I first predicted
7 0
3 years ago
Read 2 more answers
Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2
nlexa [21]

\bold{[ \ Answer \ ]}

\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}

\bold{[ \ Explanation \ ]}

  • \bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}

\bold{-------------------}

  • \bold{Rewrite}

\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Rewrite}

\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}

\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}

  • \bold{Rewrite}

\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}

  • \bold{Simplify}

\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}

\boxed{\bold{[] \ Eclipsed \ []}}

3 0
3 years ago
Read 2 more answers
can someone please help me out with this problem ? i been trying to do this for like 2 days now and i still don’t get it .. also
kotykmax [81]

Answer:

Step-by-step explanation:

the Pythagorean theorem is

c is the hypotenuse which is the side opposite of the right angle

plug the numbers into the Pythagorean theorem

x^2+(\sqrt{26})^2=13^2

when squaring a square root, just take the number in the radical and get rid of the radical

x^2+26=169

subtract 26 from both sides

x^2=143

find the square root of 143

143 is prime so it can just be written as

x=\sqrt{143}

6 0
2 years ago
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