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Mashutka [201]
2 years ago
15

1/8 + 1/4 ?? Why do I need 20 characters to summit this

Mathematics
2 answers:
abruzzese [7]2 years ago
4 0

Answer:

0.375

Step-by-step explanation:

Lera25 [3.4K]2 years ago
3 0

Answer:

1/8+1/4=3/8, and I believe you meant submit

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How would you simplify the expression represented by the diagram below? Four figures. The first consists of 4 squares each label
Sergeu [11.5K]

Answer:

6 x 3c

Step-by-step explanation:

6 0
2 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
a train leaves little rock, arkansas and travels north at 70 kilometers per hour. another train leaves at the same time and trav
jekas [21]
45 hours.
80 - 70= 10, and 450/10 is 45.
to justify, you can do 70x45= 3,150, and 80x45= (3,600 - 3,150= 450)
8 0
3 years ago
Helpppppp meeeeeeeeeeeee
denis23 [38]

Answer:

81000 people went to Bonnaroo.

192000 people went to Lollapalooza.

Step-by-step explanation:

Given:

Total number of people attending festivals, N=273000

Number of people attending Lollapalooza is 30,000 more than twice the people attending Bonnaroo.

Unknown:

Number of people attending Lollapalooza and Bonnaroo.

Let the number of people attending Bonnaroo be x.

Therefore, the number of people attending Lollapalooza is equal to 30000+2x

Evaluate:

Sum of people attending Bonnaroo and Lollapalooza is equal to the total number of people attending the festivals. So,

x+30000+2x=N\\3x+30000=273000\\3x=273000-30000\\3x=243000\\x=\frac{243000}{3}=81000

Substitute and Solve:

Now, we have, x=81000.

Substitute 81000 for x and solve for the number of people attending both the festivals. This gives,

Number of people attending Bonnaroo = x=81000

Number of people attending Lollapalooza = 30000+2x=30000+2(81000)=30000+162000=192000

Therefore, 81000 people went to Bonnaroo and 192000 people went to Lollapalooza.

8 0
2 years ago
List the prime factors for each number. is the number prime?
JulsSmile [24]
Here you go I Found a graph for you

7 0
3 years ago
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