With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
Idk...........................................................................................
No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
Could be y=8x + 16?
The gradient is 8 bcause each time x increases by one y increases by 8