Step-by-step explanation:
remember that x^-n means 1/(x^n).
x^a × x^b = x^(a+b)
x^a / x^b = x^(a-b)
(x^a)^b = x^(a×b)
(x×y)^n = x^n × y^n
so,
a^2 / a^-2 = a^(2 - -2) = a^4
and
b^-3 / b^2 = b^(-3 - 2) = b^-5 = 1/(b^5)
that means we have then :
(a^4 × b^-5)^2 = (a^4)^2 × (b^-5)^2 = a^8 × b^-10 =
= a^8 / b^10 = a⁸/b¹⁰
Answer:
Step-by-step explanation:
y=mx+b
m is slope
b is y-intercept
slope is 9/10
y-intercept is 1
7) - 1
tan <BAD = BD / AD
BC = √(64 + 36)
BC = √100
BC = 10
now you can solve BD
BD/6 = 6/10
BD = 6*6 / 10
BD = 36/10
BD = 3.6
AD = √36 - 12.96
AD = √23.04
AD = 4.8
tan <BAD = BD / AD
tan <BAD = 3.6 / 4.8
tan <BAD = 0.75
7) - 2
cos <DAC + cos <DAB
as you know cos = Adj / Hypo
cos <DAC = AD/AC
cos <DAC = 4.8 / 8
cos <DAC = 0.6
cos <DAB = AD / AB
cos <DAB = 4.8/6
cos <DAB = 0.8
so
cos <DAC + cos <DAB = 0.6 + 0.8
cos <DAC + cos <DAB = 1.4
hope it helps
Answer:The first option is correct
Step-by-step explanation: