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2 years ago

Pressure and volume are inversely related. When the pressure on a gas is doubled, what happens to the volume

Chemistry

2 answers:

Katena32 [7]2 years ago

7 0

Answer: Volume decreases to half of original volume

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

${P_1V_1}={P_2V_2}$

where,

$P_1$ = initial pressure of gas = p

$P_2$ = final pressure of gas = 2p

$V_1$ = initial volume of gas = v

$V_2$ = final volume of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

${p\times v}=2p\times V_2$

$V_2=\frac{v}{2}$

Therefore, the final volume of the gas will become half of initial volume.

Airida [17]2 years ago

5 0

When the pressure is doubled the volume will be half as the pressure increase due to the frequent collision of molecules so with the decrease in volume the pressure will increase as Boyles law

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Control of Blood pH by respiratory rate.

nata0808 [166]

Answer:

A) During this procedure ( hypoventilation ) The CO2 in the arterial blood vessels and the lungs increases and this drives the PH level in the system lower, and the equilibrium will shift to the right. this is because the Blood-PH level is controlled by CO2 - bicarbonate buffer system

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in $H^+$ which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

Explanation:

$CO_{2} +H_{2} O$ ⇄ $H^+ + HCO^-_{3}$

B) The blood PH may rise to 7.60 during Hyperventilation because the removal of CO2 from the lungs causes the increase in $H^+$ which is directly proportional to the increase in Blood PH levels

C) Hyper ventilation before a dash would be useful because it will remove excessive Hydrogen ions and and raise the Blood PH levels in preparedness of the production of acids like Lactic acid

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3 years ago

List a few of the physical properties of buckyball

stepladder [879]

Buckyball or buckminster fullerene is the third allotrope of carbon. It contains 60 carbons which are arranged in the five and six membered rings. Buckyball is the cluster of carbon atoms which are arranged in spherical shape and it forms a hollow cage.

The physical properties are:

Buckyball is made up of huge number of molecules but giant covalent bond is not exist.

The forces between the individual buckyballs are weak intermolecular forces.

The substances which are made up of buckyballs has low melting point in comparison to other allotropes of carbon as low energy is required to overcome theses intermolecular forces.

The substances which are made up of buckyballs is slippery in nature.

The solutions of buckminster fullerene are deep purple in color and upon evaporation brown residue is obtained.

Buckyball is soft in comparison to graphite and when it is compressed to less than 70 percent of its volume then, it converts into superhard form of diamond.

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3 years ago

How many moles of HCl are present in 4.7 L of a 4.23 M HCl solution?

REY [17]

Hey There!

Volume = 4.7 L

Molarity = 4.23 M

Therefore:

n = M *V

n = 4.23 * 4.7

n = 19.881 moles of HCl

hope this helps!

6 0

3 years ago

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq)+2

Setler79 [48]

Answer:

a) volume of ammonium iodide required =349 mL

b) the moles of lead iodide formed = 0.0436 mol

Explanation:

The reaction is:

$Pb(NO_{3})_{2}+2NH_{4}I -->PbI_{2}+2NH_{4}NO_{3}$

It shows that one mole of lead nitrate will react with two moles of ammonium iodide to give one mole of lead iodide.

Let us calculate the moles of lead nitrate taken in the solution.

Moles=molarityX volume (L)

Moles of lead nitrate = 0.360 X 0.121 =0.0436 mol

the moles of ammonium iodide required = 2 X0.0436 = 0.0872 mol

The volume of ammonium iodide required will be:

$volume=\frac{moles}{molarity}=\frac{0.0872}{0.250}=0.349L=349mL$

the moles of lead iodide formed = moles of lead nitrate taken = 0.0436 mol

7 0

3 years ago

At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?

ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

$Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}$

$Pressure=\frac{densityXRT}{molarmass}$

$molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50$

Thus molar mass of gas is 37.50g/mol

6 0

3 years ago