Ask question

Ask question

All categories

3 years ago

15

The r group or side chain of the amino acid serine is –ch2 -oh. the r group or side chain of the amino acid alanine is – ch3 . w

here would you expect to find these amino acids in a globular protein in aqueous solution?

1 answer:

olya-2409 [2.1K]3 years ago

8 0

Ch 5 protein mainfactured by solution

You might be interested in

. What is the density of a block of plastic if the volume of the block is 5 cm and the mass is 17.2 g?

stellarik [79]

Answer:

<h3>The answer is 3.44 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 17.2 g

volume = 5 cm³

We have

$density = \frac{17.2}{5} \\$

We have the final answer as

<h3>3.44 g/cm³</h3>

Hope this helps you

5 0

3 years ago

If the half-life of hydrogen-3 is 11.8 years, after two half-lives the radioactivity of a sample will be reduced to one-half of

maw [93]

Answer:

False

Explanation:

Half life is the time period at which the concentration of the radioactive substance in decay reduced to half.

<u>Thus, if the hydrogen-3 has gone 2 half lives, it means that it has first reduced to its half and then again the half of what it was, i.e. 1/4</u>

Thus, after two successive half-lives, the concentration must be 1/4 of the initial concentration and hence, the statement is false.

4 0

3 years ago

The pH of a vinegar solution is 4.15. What is the H+ concentration of the solution

marishachu [46]

<span>The pH of a vinegar solution is 4.15. To find the H+ concentration of the solution use the following equation -log(H+)=pH. Insert the pH into the equation to get, -log(H+) = 4.15 Rearrange the equation to get, 10^(-4.15) = H+ Finally, you can solve for H+. The hydrogen ion concentration of the vinegar solution is .0000708 M.</span>

3 0

3 years ago

Read 2 more answers

A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th

Kisachek [45]

Answer:

$pH=4.1$

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

$pH=pKa+log(\frac{[base]}{[acid]} )$

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

$pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1$

Regards.

3 0

3 years ago

How does energy flow through the food chain?

yuradex [85]

Answer:

2nd order.

Explanation:

gras, grasshopper, frog, snake, eagle

Pleas mark branliest if you are satisfied with the answer. Thanking you in anticipation.

3 0

2 years ago

Read 2 more answers