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stepladder [879]
3 years ago
14

Can someone help me pls

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

A

Step-by-step explanation:

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Congruent angles must satisfy which of the following conditions?
earnstyle [38]
No they have they same angle measure APEX
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3 years ago
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a. Suppose a BMW dealer in Fullerton, CA is trying to calculate the probability of his car sale for next week. The dealer knows
egoroff_w [7]

Answer:

0.45576

Step-by-step explanation:

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Standard Deviation = √variance

Mean = 50

= √9

= 3

z = 51 - 50/3

= 0.11111

Probability value from Z-Table:

P(x<51) = 0.54424

P(x>51) = 1 - P(x<51)

= 1 - 0.54424

= 0.45576

The probability that the dealer will sell 51 or more cars is 0.45576

8 0
3 years ago
The dimensions of a right triangle are shown in the diagram.
ryzh [129]

Answer:

18.4 cm

Step-by-step explanation:

For this problem, you would use <em>Pythagorean Theorem </em>or a^2+b^2=c^2. Don't forget that the c in the formula is always your hypotenuse or the longest side of the triangle. The a and the b are always the legs of the triangle. (It doesn't matter which leg is which letter) The hypotenuse is also always across from the 90 degree angle. <u>Picture the 90 degree angle as an arrow pointing to the hypotenuse.</u>  In this case, the hypotenuse (or c) is 20.7 cm. Now all you have to do is plug and chug! I hope this helps you and thanks for asking your question!!

3 0
2 years ago
What does a represent? <br><br> A.foci<br> B. Minor axis<br> C. Major axis <br> S. Vertices.
bulgar [2K]
C) Major axis (because its facing your upper right)
8 0
3 years ago
. Evaluate tan(α + β) = sin(????+????) / cos(????+????) to show tan(???? + ????) = tan(????)+tan(????????) / 1−tan(????) tan(???
grandymaker [24]

Answer with Step-by-step explanation:

We are given that

tan(\alpha+\beta)

\frac{sin(\alpha+\beta}{cos(\alpha+\beta)}

By using formulatan x=\frac{sin x}{cos x}

\frac{sin\alpha cos\beta+sin\beta cos\alpha}{cos\alpha cos\beta-sin\alpha sin\beta}

By using property:sin(x+y)=sin x cosy+cos x sin y

cos(x+y)=cos x cosy-sin x siny

Divide numerator and denominator by cos\alpha cos\beta

Then, we get

\frac{\frac{sin\alpha}{cos\alpha}+\frac{sin\beta}{cos\beta}}{1-\frac{sin\alpha sin\beta}{cos\alpha cos\beta}}

tan(\alpha+\beta)=\frac{tan\alpha+tan\beta}{1-tan\alpha tan\beta}

Hence, proved

Substitute \alpha=\beta

Then we get

tan 2\alpha=\frac{tan\alpha+tan\alpha}{1-tan^2\alpha}

tan(2\alpha)=\frac{2tan\alpha}{1-tan^2\alpha}

Hence, proved.

3 0
3 years ago
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