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Makovka662 [10]
2 years ago
7

∠A and \angle B∠B are vertical angles. If m\angle A=(5x-4)^{\circ}∠A=(5x−4) ∘ and m\angle B=(2x-1)^{\circ}∠B=(2x−1) ∘ , then fin

d the value of x.
Mathematics
1 answer:
lions [1.4K]2 years ago
5 0

Answer:

x=1

Step-by-step explanation:

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Find the missing side c in right triangle ΔABC, where a = 5 cm, b = 12 cm, and c is the hypotenuse of the right triangle.
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13cm because c is the hypotenuse .with formulae right angle triangle of 5^2+12^2=13
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3 years ago
Please help with this
Andreas93 [3]

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addition property of equality

Step-by-step explanation:

x-7=5 to cancel add 7 to each side

x-7+7=5+7

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Megan is one of the cheerleaders in her school. To prepare for the forthcoming Cheer Dance Competition, her coach is teaching th
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16 feet

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7 0
2 years ago
Raul has 56 bouncy balls. he puts three times as many balls into red gift bags as he puts into green gift bags. if he puts the s
Oksi-84 [34.3K]

Raul has 56 bouncy balls

he puts the balls into red gift bags and green gift bags

so lets say he puts x number of balls into green gift bags

then we are told that he puts three times as many balls into red gift bags as he puts into green gift bags

so the number of balls he puts into red gift bags is - 3 * x = 3x

the total number of balls = 56

so we can write the following equation

x + 3x = 56

4x = 56

x = 56/4

x = 14

therefore the amount of balls he puts into green bags is - 14 balls


6 0
3 years ago
Read 2 more answers
3. The average age of online consumers a few years ago was 23.3 years with a standard deviation of 5.3 years. It is believed the
Slav-nsk [51]

Answer:

We cant say, with α =0.01, that the average age changed. The p-value is 0.014

Step-by-step explanation:

As a consecuence of the Central Limit Theorem, the mean sample has a distribution approximately normal, with unknown mean and standard deviation \sigma = 5.3/\sqrt{20} = 1.1851 (the standard deviation of one single sample divided by the  sqaure root of the sample lenght).

The null hypothesis H₀ is that the average age is still 23.3 (the mean is 23.3). The alternative hypothesis is that the mean is different. We want to see if we can refute H₀ with significance level α =0.01.

Lets call X the mean of a random sample of 20 online shoppers. As we discuse above, X is approximately normal with unknown mean and standard deviation equal to 1.1851 . If we take the hypothesis H₀ as True, then the mean will be 23.3, and if we standarize X, we have that the distribution

W = \frac{X - 23.3}{1.1851}

Will have a distribution approximately normal, with mean 0 and standard deviation 1.

The values of the cummulative ditribution of the normal function can be found in the attached file. Since we want a significance level of 0.01, then we need a value Z such that

P(-Z < W < Z) = 0.99

For the symmetry of the standard Normal distribution, we have that Φ(Z) = 1-Φ(-Z), where Φ is the cummulative distribution function of the standard Normal random variable. Therefore, we want Z such that

Φ(Z) = 0.995

If we look at the table, we will found that Z = 2.57, thus,

0.99 = P(-2.57 < W < 2.57) = P(-2.57 < \frac{X-23.3}{1.1851} < 2.57)\\ = P(-2.57*1.1851 + 23.3 < X < 2.57*1.1851 + 23.3) = P(20.254 < X < 26.345)

Thus, we will refute the hypothesis if the observed value of X lies outside the interval [20.254, 26.345].

Since the observed value is 26.2, then we dont refute H₀, So we dont accept that the number average age of online consumers has changed.

For us to refute the hypothesis we need Z such that, for the observed value, |W| > Z. Replacing X by 26.2, we have that [tex] W = \frac{26.2-23.3}{1.1851} = 2.4470. We can observe that Φ(2.447) = 0.993, substracting that amount from 1 and multiplying by 2 (because it can take low values too), we obtain that the p-value is 0.014.  

Download pdf
8 0
3 years ago
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