1.40 as a fraction is a 1 40/100 simplify it. 1 20/50. 1 2/5
HOPE I HELPED!!!
1. Multiply each equation so they end up with the same coefficient
2. Subtract your second equation from the first
3. Solve for one of the variables (I tend to solve an equation that only contains 2 variables if possible. So it would be if you have one question with x and y, solve for the easier one)
4. Substitute the variable you found in the least step into one of the other equations and find a second variable.
5. Substitute both variables you found into the last equation and there you should be left with x, y, and z :))
I hope this helped sksjsk if it didn’t I could write it out to hopefully help more :)
Answer:
Step-by-step explanation:
<u><em>The correct question is</em></u>
Solve. −3/5x+1/5>7/20 Drag and drop a number or symbol into each box to show the solution
we have
Solve for x
Multiply by 20 both sides
subtract 4 both sides
divide by -12 both sides
Remember that when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol
simplify
Answer:
Step-by-step explanation:
Hello!
The chemistry instructor tested the hypothesis that the proportion of students that passed the introductory chemistry class is better with an embedded. If the known proportion for this population is 65%, the tested hypothesis is:
H₀: p=0.65
H₁: p>0.65
The calculated statistic is Z=2.52 and the associated p-value: 0.0059
Remember:
The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).
In this case:
P(Z≥2.52)=0.0059
There is no significance level, the most common one is α: 0.05 so I'll use it as an example.
To make a decision using the p-value you have to compare it to the α.
If p- value>α then you support the null hypothesis (In this case, you can say that there is no change in the proportion of students that passed the introductory chemistry class with an embedded tutor.)
If p-value≤α your decision will be to reject the null hypothesis (In this case, there is significant evidence to say that there is an improvement in the success rate of the introductory chemistry class with an embedded tutor?
Since the p-value:0.0059 is less than the significance level 0.05, you will decide to reject the null hypothesis.
I hope you have a SUPER day!
