Ask question

Ask question

All categories

3 years ago

9

Which word phrases represent the variable expression m – 11? Choose all answers that are correct. A. 11 more than a number B. th

e difference of a number and 11 C. the quotient of a number and 11 D. 11 less than a number

1 answer:

Rashid [163]3 years ago

7 0

B and D would both be correct for m-11

You might be interested in

the riches are ordering topsoil for their new lawn. the topsoil will be spread evenly over the yard before the grass is planted

Alexus [3.1K]

81ft(yd/3ft)*111ft(yd/3ft)*2in(yd/36in)=55.5 yd^3

So 55 1/2 cubic yards of topsoil are needed.

6 0

3 years ago

Read 2 more answers

Draw the multiplication table on the P=(3,5,7,9) in module 12

Lisa [10]

Answer:

Find the attached file for the solution

Step-by-step explanation: To draw the multiplication table on the P=(3,5,7,9) in module 12, create the table where all the given parameters will be at the top of horizontal axis and vertical axis,

When multiply by each other, any value that is below 12 will be written down while the value greater than 12 will be divided by 12 and the remainder will be written down.

Find the attached file for the solution and table.

8 0

3 years ago

NEED ANSWER ASAP PLEASE

ollegr [7]

I don't get how it would be a system of equations.

3 0

3 years ago

Read 2 more answers

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

Solve for y hdgkgsydkydutskgxtisit

Feliz [49]

You said X = (5y+1) / (y-2)

Multiply each side by (y-2):

X(y-2) = (5y+1)

Eliminate parentheses:

Xy - 2X = 5y + 1

Add 2X to each side:

Xy = 5y + 1 + 2X

Subtract 5y from each side:

(X-5)y = 1 + 2X

Divide each side by (X-5):

<em>y = (1+2X) / (X-5) </em>

7 0

3 years ago

Read 2 more answers