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kenny6666 [7]
2 years ago
11

Pleaseee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics
1 answer:
solniwko [45]2 years ago
5 0
ANSWER: FG = 69

FG = FK + KG
KG = 1/2(FK)
FK = 46

RULE: When it comes to centroids, the longer section of the line is always 2/3 of the entire line (+ the shorter section of the line is always 1/3). This means that the shorter section of the line is HALF of the longer section of the line.

FG = FK + KG
FG = 46 + 46/2
FG = 46 + 23
FG = 69

CHECK:
FK = 2/3(FG)
46 = 2*69/3
46 = 138/3
46 = 46 ✔️

or

KG = 1/3(FG)
1/2(FK) = 1/3(FG)
46/2 = 69/3
23 = 23 ✔️
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A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p
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Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

<u>step 1:-</u>

Given sample  size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

 Population proportion of employed individuals who work at home at least once per week  P = \frac{x}{n} =\frac{41}{200} =0.205

Q=1-P= 1-0.205 = 0.705

<u>step 2:-</u>

Now  \sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }

=0.0015

<u>step 3:-</u>

<u>Confidence intervals</u>

<u>using formula</u>

(P  -  Z_∝} \sqrt{\frac{P Q}{n},} (P  +  Z_∝} \sqrt{\frac{P Q}{n},

(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887

=0.20113,0.20887[/tex]

<u>conclusion:</u>-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

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