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3 years ago

Develop an algorithm to compute and print out the average of 3 numbers A,B,C

Computers and Technology

1 answer:

OLga [1]3 years ago

3 0

Answer:

Input: Take 3 numbers A, B and C

Processing: Find average of 3 numbers using formula: Average= A+B+C/3

Output: The output is Average of three numbers.

Explanation:

We need to write an algorithm to compute and print out the average of 3 numbers A,B,C

An algorithm has Input, Processing and Output

The algorithm required is:

Input: Take 3 numbers A, B and C

Processing: Find average of 3 numbers using formula: Average= A+B+C/3

Output: The output is Average of three numbers.

You might be interested in

Assume that a kernel is launched with 1000 thread blocks each of which has 512 threads. If a variable is declared as a shared me

Alex

Answer:

The answer to this question is the option "B".

Explanation:

In this question, the answer is option B which is 1,000 because the kernel is a central part of an operating system. kernel manages the computer and the hardware operations. most especially memory and CPU time. It also sheared a memory variable is allocated to thread blocks. That's why the answer to this question is 1,000.

7 0

3 years ago

Write a function called factor that determines for a pair of integers whether the second integer is a factor of the first. The f

Aleks04 [339]

<h2>Answer:</h2>

//import the Scanner class to allow for user's input

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

//Declare the function factor

//It returns either true or false, therefore the return type is boolean

//It receives two arguments - a and b

public static boolean factor(int a, int b){

//Check if a is divisible by b.

//Return true if yes

if(a % b == 0){

return true;

}

//return false if a is not divisible by b

return false;

} // End of method factor

//The main method to test the function factor()

public static void main(String[] args) {

//Create an object of the Scanner class

Scanner input = new Scanner(System.in);

//Prompt the user to enter the pair of numbers

System.out.println("Enter the pair of numbers (separated by a space)");

//grab and store the first number in a variable

int firstnum = input.nextInt();

//grab and store the second number in another variable

int secondnum = input.nextInt();

//With the variables, call the factor() method

//If it returns true, print the adequate message

if(factor(firstnum, secondnum)){

System.out.println(secondnum + " is a factor of " + firstnum);

}

//If it returns false, print the adequate message

else{

System.out.println(secondnum + " is NOT a factor of " + firstnum);

}

} // End of main method

} // End of class declaration

==============================================================

<h2>Sample Output 1:</h2>

>> Enter the pair of numbers separated by a space

8 4

>> 4 is a factor of 8

==============================================================

<h2>Sample Output 2:</h2>

>> Enter the pair of numbers separated by a space

9 4

>> 4 is NOT a factor of 9

==============================================================

<h2>Explanation:</h2>

The above code has been written in Java and it contains comments explaining every segment of the code. Kindly go through the comments for better understanding of the code.

For simplicity, the code is re-written as follows with little or no comments;

import java.util.Scanner;

//Declare the class and call it FactorClass

public class FactorClass {

public static boolean factor(int a, int b) {

if(a % b == 0){

return true;

}

//return false if a is not divisible by b

return false;

} // End of method factor

//The main method to test the function factor()

public static void main(String[] args) {

//Create an object of the Scanner class

Scanner input = new Scanner(System.in);

//Prompt the user to enter the pair of numbers

System.out.println("Enter the pair of numbers (separated by a space)");

//grab and store the first number in a variable

int firstnum = input.nextInt();

//grab and store the second number in another variable

int secondnum = input.nextInt();

if(factor(firstnum, secondnum)){

System.out.println(secondnum + " is a factor of " + firstnum);

}

else{

System.out.println(secondnum + " is NOT a factor of " + firstnum);

}

3 0

3 years ago

3. In a 32-bit CPU, the largest integer that we can store is 2147483647. Verify this with a

Semenov [28]

Answer:

No, it can't be verified with a pseudocode.

Explanation:

We can not verify this with a pseudocode because the largest integer that we can store in 32-bit integer goes by the formula 2^32 - 1 = 4, 294, 967,295 and this means that it has 32 ones. Or it may be 2^31 - 1 = 2, 147, 483,647 which is a two complement signed integer.

Despite the fact that it can not be verified by using pseudocode, we can do the Verification by writting programs Through some programming language or in plain English code.

In a 32-bit CPU, the largest integer that we can store is 2147483647 because we can store integer as 2^31 and - (2^31 + 1).

5 0

3 years ago

If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support

Molodets [167]

Answer:

Here is the JAVA program. I have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); // create object of Scanner

String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

String LOL = "laughing out loud";

String IDK = "i don't know";

String BFF = "best friends forever";

String IMHO = "in my humble opinion";

String TMI = "too much information";

String TYT = "take your time";

String IDC = "I don't care";

String FYI = "for your information";

String BTW = "by the way";

String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

System.out.println("Input an abbreviation:" + " ");

if(input.hasNext()) { // reads the abbreviation form the user

abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

switch(abbreviation) {

case "LOL" : System.out.println(LOL);

break;

case "IDK" : System.out.println(IDK);

break;

case "BFF" : System.out.println(BFF);

break;

case "IMHO": System.out.println(IMHO);

break;

case "TMI": System.out.println(TMI);

break;

case "TYT": System.out.println(TYT);

break;

case "IDC": System.out.println(IDC);

break;

case "FYI": System.out.println(FYI);

break;

case "BTW": System.out.println(BTW);

break;

case "OMG": System.out.println(OMG);

break;

default : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.