The function involves the initial speed of the object, and the height
from which it was launched, and whether it was launched upward
or downward. As you can see, your post was corrupted and is
unreadable. But when the object hits the ground, its height is zero.
Set the function equal to zero, solve the quadratic equation that you
have, discard the negative solution, and the positive solution is your
answer.
The rate of change of the distance from the particle to the origin at this instant is 3 units per second.
<h3>What is the rate of change?</h3>
The instantaneous rate of change is the rate of change at a particular instant.
A particle is moving along the curve

The rate of change of y is given as:
dy / dx = 2
by differentiating both sides,

From the question, we have:
(x, y) = (5,24)
Substitute 5 for x and dy / dx = 2

Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.
Read more about rates of change at:
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Answer:
f(x) = x³ - x² - 4x + 4
Step-by-step explanation:
Given the zeros of a polynomial say x = a, x = b, x = c then
(x - a), (x - b), (x - c) are the factors of the polynomial and
f(x) is the product of the factors
here x = 1, x = - 2, x = 2, hence
(x - 1),(x + 2), (x - 2) are the factors and
f(x) = a(x - 1)(x + 2)(x - 2) ← a is a multiplier
let a = 1 and expand the factors
f(x) = (x - 1)(x² - 4)
= x³ - 4x - x² + 4
= x³ - x² - 4x + 4 ← in standard form
Answer:
420 minutes
Step-by-step explanation:
7:30am to 2:30pm
=7:30to 14:30
=14.30-7.30=
7hours
in minutes;
7×60
= 420minutes
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Answer:

Step-by-step explanation:
Given
-- Objective function
Constraints:



Required
Minimum value of E
To do this, we apply graphical method
See attachment for plots of
and 
From the attached plot, the point that satisfy
is:

So, we have:

This gives:


