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slavikrds [6]
3 years ago
5

Apply distributive property to factor out the GCF 27+18r=

Mathematics
1 answer:
leva [86]3 years ago
8 0

Answer: 9(3 + 2r)

<u>Step-by-step explanation:</u>

      27                     18r

       ∧                       ∧

    <u>3</u>  9                    <u>2</u>  9r

         ∧                         ∧

        <u>3</u>  <u>3</u>                     <u>3</u> <u>3r</u>

27: 3 * 3 * 3

18r: 2 * 3 * 3 * r

Common Factors are 3 * 3 = 9

27: 9 * <u>3</u>

18: 9 * <u>2r</u>

27 + 18r  =  9(3 + 2r)

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Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
3 years ago
Can someone please help
Juliette [100K]

Answer:

201.06

Step-by-step explanation:

3.14 * 8^2= 201.06

(pi * radius ^ squared)

5 0
3 years ago
Read 2 more answers
ABC has been translated 5 units to the right, as shown in the diagram. What is the length of ?
BARSIC [14]

Answer:

(A) 15 centimeters

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Parallel to the bottom of the triangle.

Since ABC is an equilateral triangle, we know that EVERY side is 30cm, including AC.

So the midsegment of ABC, LM, must be 15 cm.

Hope this helped!

6 0
3 years ago
CD and CB are tangent to circle A. If CD = 5x – 13 and CB = 12, find x.<br>​
hoa [83]

Answer:

5

Step-by-step explanation:

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