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SVETLANKA909090 [29]
3 years ago
15

Can someone explain or solve these || scale drawings

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

1. 425 kilometers

2. 780 kilometers

Step-by-step explanation:

1. 50×8.5= 450 kilometers

2. 65×12=780 kilometers

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What is 8 (x+y) - 4 (x-y) ?
tankabanditka [31]

Answer:

4X+12 y

Step-by-step explanation:

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8 0
3 years ago
Again(sorry) did anyone know 96 and 97
vladimir2022 [97]
96: 

sugar: 1,2,3,4,5,6
flour:2,4,6,8,10,12

97:

yellow:3,6,9,12,15,18
blue:1,2,3,4,5,6
7 0
3 years ago
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If A= (6,11), B= (1,5), and C= (7,0), show by means of slopes that ABC is a right triangle. Name the hypotenuse.
nexus9112 [7]

Since the product of AB and BC is -1, hence the ABC is a right triangle and the length AC is the hypotenuse

<h3>Right angled triangle</h3>

A right angles triangle is a triangle that has 3 sides and angles with one of its angles to be 90 degrees.

For the given coordinates to be a right angled triangle, one of the line must be perpendicular to the other and for two lines to be perpendicular, the product of its slope must be -1.

Find the slopes of AB, BC and AC

Slope of AB = 5-11/1-6
Slope of AB = -6/-5 = 6/5

Slope of BC = 0-5/7-1
Slope of BC = -5/6

Slope of AC = 0-11/7-6
Slope of AC = -11/1. = -11

Take the product of AB and BC
AB * BC = 6/5 * -5/6
AB * BC = -1

Since the product of AB and BC is -1, hence the ABC is a right triangle and the length AC is the hypotenuse

Learn more on right angle triangle here: brainly.com/question/22790996

#SPJ1

6 0
2 years ago
Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=x-7%20%3D%2010" id="TexFormula1" title="x-7 = 10" alt="x-7 = 10" align="absmiddle" class="late
Artist 52 [7]

Answer:

This is your answer <( ̄︶ ̄)↗

Step-by-step explanation:

.

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plz mark me a brainlist..

#hope it helps you..

(◕ᴗ◕)

3 0
2 years ago
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