Answer:
Option C. f(n) = 16(3/2)⁽ⁿ¯¹⁾
Step-by-step explanation:
To know which option is correct, do the following:
For Option A
f(n) = 3/2(n – 1) + 16
n = 1
f(n) = 3/2(1 – 1) + 16
f(n) = 3/2(0) + 16
f(n) = 16
n = 2
f(n) = 3/2(n – 1) + 16
f(n) = 3/2(2 – 1) + 16
f(n) = 3/2(1) + 16
f(n) = 3/2 + 16
f(n) = 1.5 + 16
f(n) = 17.5
For Option B
f(n) = 3/2(16)⁽ⁿ¯¹⁾
n = 1
f(n) = 3/2(16)⁽¹¯¹⁾
f(n) = 3/2(16)⁰
f(n) = 3/2 × 1
f(n) = 1
For Option C
f(n) = 16(3/2)⁽ⁿ¯¹⁾
n = 1
f(n) = 16(3/2)⁽¹¯¹⁾
f(n) = 16(3/2)⁰
f(n) = 16 × 1
f(n) = 16
n = 2
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽²¯¹⁾
f(n) = 16(3/2)¹
f(n) = 16(3/2)
f(n) = 8 × 3
f(n) = 24
n = 3
f(n) = 16(3/2)⁽ⁿ¯¹⁾
f(n) = 16(3/2)⁽³¯¹⁾
f(n) = 16(3/2)²
f(n) = 16(9/4)
f(n) = 4 × 9
f(n) = 36
For Option D
f(n) = 8n + 8
n = 1
f(n) = 8(1) + 8
f(n) = 8 + 8
f(n) = 16
n = 2
f(n) = 8n + 8
f(n) = 8(2) + 8
f(n) = 16 + 8
f(n) = 24
n = 3
f(n) = 8n + 8
f(n) = 8(3) + 8
f(n) = 24 + 8
f(n) = 32
From the above illustration, only option C describes the sequence.
Answer:
30 first-class tickets were sold and 260 coach tickets were sold.
Step-by-step explanation:
Let a first-class ticket be represented by f and let a coach ticket be represented by c.
On a particular flight, a jumbo jet was carrying 290 passengers. So, the sum of the first-class tickets and coach tickets must sum to 290:
The total income was $95,280. Therefore:
We can now solve the system of equations. First, we can simplify the second equation by dividing everything by 8:
From the first equation, we can subtract f from both sides:
Substitute:
Distribute:
Simplify:
So:
From the previous equation:
Substitute:
30 first-class tickets were sold and 260 coach tickets were sold.
The answer is B because you would multiply 3 with 2 giving you a total of 6 and then you add the 2 and you get 8
6/30 = 1/5
This means that 1/5 of the students in a class will be left-handed.
27*5 = 135
27/135 = 1/5
The correct answer is 135 students.
