Answer:
tan(2u)=[4sqrt(21)]/[17]
Step-by-step explanation:
Let u=arcsin(0.4)
tan(2u)=sin(2u)/cos(2u)
tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]
If u=arcsin(0.4), then sin(u)=0.4
By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.
This also implies cos(u)=sqrt(0.84) since cosine is positive.
Plug in values:
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]
tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]
tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]
tan(2u)=[(40)(sqrt(0.84)]/[34]
tan(2u)=[(20)(sqrt(0.84)]/[17]
Note:
0.84=0.04(21)
So the principal square root of 0.04 is 0.2
Sqrt(0.84)=0.2sqrt(21).
tan(2u)=[(20)(0.2)(sqrt(21)]/[17]
tan(2u)=[(20)(2)sqrt(21)]/[170]
tan(2u)=[(2)(2)sqrt(21)]/[17]
tan(2u)=[4sqrt(21)]/[17]
First - 8
second - 4
third - 12
fourth - 9
Answer:
Step-by-step explanation:
The domain of this relation (not a function) is x = -5. The relation is not defined for any other x value.
Answer:
1/2
Step-by-step explanation:
1/2=10/20
Answer:
D 8√(10) ^3x
Step-by-step explanation:
We have
sqrt(10) ^ (3/4x)
We can rewrite the sqrt as ^1/2
10 ^ (1/2) ^ (3/4x)
We know that a^b^c = a^(b*c)
10 ^(1/2 *3/4x)
10 ^(3/8 x)
The numerator is the power
The denominator is the root
8√(10) ^3x
