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eduard
3 years ago
15

Which of the following is not a factor of 4x^3+12x^2-72x? a.(x+9) b.(x-3) c.4x d.(x+6

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
7 0

Answer:

x+9

Step-by-step explanation:

4x³+12x²-72x

=4x(x²+3x-18)

=4x[x²+6x-3x-18]

=4x[x(x+6)-3(x+6)]

=4x(x+6)(x-3)

guapka [62]3 years ago
5 0
The correct answer is x+9
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The question with the distributive property
kondor19780726 [428]

6(a+2b+3c)

=(6)(a)+(6)(2b)+(6)(3c)

=6a+12b+18c

Hope this helps




7 0
3 years ago
7 (8.02) need answer asap
timama [110]
Both groups are similar.
7 0
3 years ago
Please help work this out
BigorU [14]

Answer:

Area=190.091 cm^2

Step-by-step explanation:

Area = 1/2(Pi x r^2)    one-half because it's a semi-circle

Area=1/2(3.14 x 11^2)

11^2=121 so, Area=1/2(3.14 x 121)

Area=1/2(379.94)

Area=189.97 cm^2

adjustment:

Area=1/2(3.142 x 11^2)

Area=1/2(3.142 x 121)

Area=1/2(380.182)

Area=190.091

5 0
3 years ago
The area of a circle is 161 in. What is the radius?​
kirill [66]

Answer:

Approximately 7.16 in

Step-by-step explanation:

Hi there!

Area of a circle equation: A=\pi r^2 where r is the radius

Plug in the given area 161 in.²

161=\pi r^2

Divide both sides by π to isolate r²

\frac{161}{\pi} =\frac{\pi r^2}{\pi} \\\frac{161}{\pi} =r^2

Take the square root of both sides to isolate r

=r^2\\\sqrt{\frac{161}{\pi}} =r\\7.16=r

Therefore, the radius of the circle is approximately 7.16 in.

I hope this helps!

7 0
3 years ago
A student wants to construct a circumscribed circle of a triangle. What is the first step he should take?
Ray Of Light [21]

<u>Answer:</u>

The correct answer option is B. Construct the perpendicular bisector of each side of the triangle.

<u>Step-by-step explanation:</u>

We are given that a student wants to construct a circumscribed circle of a triangle and we are to determine whether which of the given answer options is the first step he should take.

The student needs to first construct the perpendicular bisector of each side of the triangle.

The perpendicular bisectors of each side of the triangle are constructed such that they meet at the center of the circumbscribed circle.

4 0
3 years ago
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