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3 years ago

Which of the following is not a factor of 4x^3+12x^2-72x? a.(x+9) b.(x-3) c.4x d.(x+6

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

7 0

Answer:

x+9

Step-by-step explanation:

4x³+12x²-72x

=4x(x²+3x-18)

=4x[x²+6x-3x-18]

=4x[x(x+6)-3(x+6)]

=4x(x+6)(x-3)

guapka [62]3 years ago

5 0

The correct answer is x+9

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Write the equation of the line with the following characteristics.

Alika [10]

Answer:

y = 7x

y = 2x -3

y = 3

x = -2

Step-by-step explanation:

Slope-intercept form: y= mx+b
Parallel lines have same slope

a)Parallel to y=7x+2 through the point (0,0)

This line will have a form:

y= 7x + b

Considering the given point of (0,0), to find the value of b:

0= 7*0+b ⇒ b =0

The line is:

y = 7x

b)Slope of 2 through the point (0,−3)

Solving as above:

y= 2x + b
-3 = 2*0 + b ⇒ b = -3
y = 2x -3

c)A horizontal line through the point (0,3)

A horizontal line will have constant value for y for any value of x:

y = 3

d)A vertical line through the point (−2,0)

A vertical line will have constant value of x for any value of y:

x= -2

5 0

3 years ago

Rewrite the form In exponential form: Log100 = x

andrey2020 [161]

Answer:

$10^x=100$

Step-by-step explanation:

You know how subtraction is the opposite of addition and division is the opposite of multiplication? A logarithm is the opposite of an exponent. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that $3^2=9$ ; as a logarithm, the exponent gets moved to its own side of the equation, and we write the equation like this: $\log_3{9}=2$ , which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like $\log1000$ uses base 10, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression $\log100=x$ means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is $10^x=100$ .