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slavikrds [6]
3 years ago
12

PLEASE HELP ASAP! THANKS SO MUCH!

Mathematics
2 answers:
givi [52]3 years ago
8 0

The answer is 2565 if u devide and multiply

rewona [7]3 years ago
3 0

$2,565

Divide 324 by 12 to get the price for one and multiply the answer by 95.

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What is 1/4 of 3/5 of customers
shepuryov [24]
The answer is 7/20. 1/4= 5/20 and 3/5 = 12/20 What I did was find the GCF (greatest common factor) of both 4 and 5 which was 20. Then I multiplied both numerators by the same number I multiplied the denominator with. Afterwards I subtracted both numerators (12-5) and this equals to 7 Hope that helps
8 0
3 years ago
Please help! Brainliest and 5 star given
goldfiish [28.3K]

Answer:

for second question

first length is 9cm

Area=l*b

= 9cm *9cm

=81<em><u>cm</u></em>

then, For semicircle

radius is 9 cm

area= 1/2*9cm

now , area of two semi circle = 2*1/2*9

= 9 cm

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3 years ago
Which shows the list of numbers in order from least to greatest?
nirvana33 [79]

Answer:

-1, |-2|, |-3|, |3.5|, |3²|

Step-by-step explanation:

  • Calculate the absolute value (the absolute value of any number is always positive): 3, 3², 2 , 3.5, -1
  • Calculate the exponents : 3, 9, 2 , 3.5, -1
  • Put in order least to greatest : -1, |-2|, |-3|, |3.5|, |3²|
3 0
2 years ago
A cone with diameter 20 cm and a height of 20 cm. Find the volume of the cone rounded to the nearest tenth.
zhuklara [117]

Answer:

2094.4 cm³

Step-by-step explanation:

The volume of a cone =πr²h/3

Where

r = radius = Diameter/2

Diameter = 20cm, radius = 20cm/2 = 10cm

Height = 20cm

Volume of a cone = π × 10² × 20/3

Volume of a cone = 2094.3951 cm³

Approximately to the nearest tenth = 2094.4 cm³

Therefore , the volume of a cone = 2094.4 cm³

8 0
3 years ago
Mhanifa can you please help? Look at the picture attached. I will mark brainliest!
Nikitich [7]

Answer:

<u>Given rhombus ABCD with</u>

  • m∠EAD = 67°, CE = 5, DE = 12

<u>Properties of a rhombus:</u>

  • All sides are congruent
  • Diagonals are perpendicular
  • Diagonals are angle bisectors
  • Diagonals bisect each other

<u>Solution, considering the above properties</u>

  • 1. m∠AED = 90°, as angle between diagonals
  • 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
  • 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
  • 4. AE = CE = 5, as E is midpoint of AC
  • 5. BE = DE = 12, as E is midpoint of BD
4 0
3 years ago
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