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Ray Of Light [21]
3 years ago
7

8×3÷(4²-13)+5²+4×3 Arrange the steps in the order in which they are preformed

Mathematics
1 answer:
mina [271]3 years ago
6 0

<u>The following are the evaluation steps in order for the 8 \times 3 \div\left(4^{2}-13\right)+5^{2}+4 \times 3 given expression:</u>

Step 1: First perform exponentiation inside parentheses

             4^{2}

Step 2: Next, evaluate the contents of parentheses

               (16 – 13)

Step 3: Before any multiplication or division, exponentiation outside parentheses should be done.

               5^{2}

Step 4: Perform multiplication and division from left to right

                8 \times 3

Step 5: Perform multiplication and division from left to right

              \frac{24}{3}

Step 6: Perform multiplication and division from left to right

                4 \times 3

Step 7: After all the multiplication and division, addition should be performed from left to right

                  (8 + 25)  

Step 8: Perform addition from left to right

                    (33 + 12)

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Answer:

1/4

Step-by-step explanation:

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4 0
3 years ago
Select all that apply. the theorems in the lesson are followed by which of the following?
musickatia [10]

Answer: E


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3 years ago
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Hey can u answer my math question look atbthe picture to see<br> the pic.​
Anna35 [415]

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4 3/4 yards

Step-by-step explanation:

5 1/4 + 2 1/2 = 7 3/4

(1/2 is equal to 2/4)

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Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r
likoan [24]

The value of q(x) is 2 x+5

The value of r(x) is 6

Explanation:

The given expression is \frac{2 x^{2}+13 x+26}{x+4}

We need to rewrite the expression in the form of q(x)+\frac{r(x)}{b(x)}

Simplifying the expression, we get,

\frac{2 x^{2}+8 x+5x+26}{x+4}

Separating the fractions, we have,

\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}

2 x+\frac{5 x+26}{x+4}  -----------(1)

Now, we shall further simplify the term \frac{5 x+26}{x+4} , we get,

\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}

Common out 5 from the numerator, we have,

\frac{5 x+26}{x+4}=5+\frac{6}{x+4}

Substituting the value \frac{5 x+26}{x+4}=5+\frac{6}{x+4} in the equation(1), we get,

2 x+5+\frac{6}{x+1}

Thus, the expression \frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1} is in the form of q(x)+\frac{r(x)}{b(x)}

Hence, we have,

q(x)=2 x+5

r(x)=6 and

b(x)=x+4

5 0
3 years ago
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