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natita [175]
3 years ago
7

What would happen if we didn't have subcutaneous fat

Biology
1 answer:
Soloha48 [4]3 years ago
3 0

Answer:

What would happen if we didn't have subcutaneous fat?

Ans) For instance, while fat has been blamed for heart attacks, strokes,diabetes, and a host of other serious illnesses, researchers are finding that low fat levels may make us even more vulnerable to death from those conditions. In many studies, being overweight actually lowers morality from disease.

<h3>Hope it's helpful to u...</h3>
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Which describes the dependent variable in an experiment
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<span>It is the variable in an experiment is not directly altered</span>
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Identify how many amino acids exist in nature and make up all proteins in living organisms.
marusya05 [52]

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The answer is 20 amino acids

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Which helps prevent errors in DNA replication?
nataly862011 [7]

Answer is: each base can attch to only one other type of base

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In a population of rabbits, there are 496 black rabbits and 27 white rabbits. Fur color is determined by a pair of alleles where
Troyanec [42]

Answer:

0.96

Explanation:

It is given that

B is the dominant allele which represents the black color

and b is the recessive allele which represents the white fur.

B being dominant will result into black color fur for genotype "Bb"

Given -

Frequency of black fur allele (p) is 0.8

As per Hardy Weinberg's  first law of equilibrium

p + q = 1\\

Substituting the value of p in above equation, we get -

q = 1-p\\q = 1-0.8\\q= 0.2

q represents the frequency for white fur allele

Frequency of white fur phenotype is

q^2\\= 0.2^2\\= 0.04

Frequency of homozygous black fur phenotype (BB) is

p^2\\= 0.8^2\\= 0.64

As per Hardy Weinberg's second law of equilibrium -

p^2 + q^2 + 2pq = 1\\0.64 + 0.04 + 2pq = 1\\2pq = 1 - 0.68\\2pq = 0.32\\

Combined frequency of homozygous and heterozygous black fur phenotype is

0.64 + 0.32\\= 0.96

5 0
2 years ago
A plasmid contains the gene for tetracycline resistance and a lacz gene that has a restriction site in it. Foreign dna has the s
tester [92]

Answer:

The colonies are carrying the resistance genes from plasmids

Explanation:

Bacteria can acquire beneficial characteristics that they didn’t have. One way for these is through plasmids, which ones are little fragments of DNA that usually contains resistance genes (for antibiotics, disinfectants, heavy metals, etc.) or other capacities, like the ability to use some substances (for example sugars).

In this specific situation, we already know that the plasmid carrying genes for tetracycline resistance and the <em>lacZ</em> gene.  

A little explanation:

Tetracycline is an antibiotic that inhibits bacterial growth and kills the bacteria.  The bacteria can “fight” to this antibiotic if it has a resistant gene, the result is that the antibiotic can’t affect the bacteria and survive.  An analogy is like a Police Officer (bacteria) that have a bulletproof vest (tetracycline-resistant gene) so the bullets (tetracycline) didn’t affect the police.

In the case of X-gal, is a compound consisting primarily in one sugar called galactose. Not all bacteria can eat galactose, they need an enzyme called β- galactosidase (comes from <em>lacZ</em> gene) that helps the bacteria “eat” the sugar (cuts the sugar in little pieces so the bacteria can eat).  

Then, as the bacterial colonies can grow in the medium with tetracycline and X-gal,  we know that those bacteria are carrying the resistance genes for tetracycline (does not affect the bacteria) and the <em>lacZ</em> gene (bacteria produce β- galactosidase that cuts galactose). These genes are coming from the plasmids because we already know that the plasmid carries these genes and not from the exogenous DNA.  

7 0
2 years ago
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