Answer:
The percentage (%) of the alleles that code for this trait in the population will increase, as more individuals are born with the trait.
Explanation:
The more individuals get born expressing the trait, the higher its frequency gets in the population. By generation, there are more individuals carrying the allele for the advantageous trait. These individuals reproduce and increase the probabilities of the progeny to inherit the mentioned allele. When this sequence keeps occurring in the population over many generations, the allele percentage will increase. On the other hand, the other allele or alleles will decrease. Probably, if there are no changes that might influence or affect this pattern, the alleles for the advantageous trait will fixate, while the other allele might get lost.
Bacteria were first observed by the Dutch microscopist Antonie van Leeuwenhoek in 1676
<u>-TheUnknownScientist</u>
Answer: It's the cells, just without the chloralplast , but animals don't need that because only plant cells have chloralplast. So animals only get theses type of cells if they a herbivores,or omnivores because they eat plants and it helps them survive that way
Explanation:
Explanation:
Biological hazards include microorganisms such as bacteria, viruses, yeasts, molds and parasites. Some of these are pathogens or may produce toxins. A pathogenic microorganism causes disease and can vary in the degree of severity
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
